您好我有PHP脚本来检索图像和文件名。我已成功获得图像和文件名。这没有问题。转换为二进制文件后,我想将其保存为服务器上的图像。但我无法保存该图像。这是我的PHP脚本。
<?php
// Get image string posted from Android App
$base=$_REQUEST['image'];
// Get file name posted from Android App
$filename = $_REQUEST['filename'];
// Decode Image
$binary=base64_decode($base);
header('Content-Type: bitmap; charset=utf-8');
// Images will be saved under 'www/imgupload/uplodedimages' folder
$file = fopen('uploadedimages/'.$filename, 'wb');
// Create File
fwrite($file, $binary);
fclose($file);
echo 'Image upload complete, Please check your php file directory\n';
?>
答案 0 :(得分:1)
这是一个简单的代码,用于在我的网络服务器上存储图像,它不会将图像转换为二进制文件,但它可以将图像存储到服务器上。
您应该创建一个uploads
文件夹,并为其提供777
等完整权限。
<?php
echo $_FILES['image']['name'] . '<br/>';
//ini_set('upload_max_filesize', '10M');
//ini_set('post_max_size', '10M');
//ini_set('max_input_time', 300);
//ini_set('max_execution_time', 300);
$target_path = "uploads/";
$target_path = $target_path . basename($_FILES['image']['name']);
try {
//throw exception if can't move the file
if (!move_uploaded_file($_FILES['image']['tmp_name'], $target_path)) {
throw new Exception('Could not move file');
}
echo "The file " . basename($_FILES['image']['name']) .
" has been uploaded";
} catch (Exception $e) {
die('File did not upload: ' . $e->getMessage());
}
?>
链接到php文件的HTML(供您参考)
<html>
<head>
<title>Upload</title>
</head>
<body>
<form enctype="multipart/form-data" action="fileUpload.php" method="POST">
Select a file<input name="image" type="file" /><br />
<input type="submit" value="Upload File" />
</form>
</body>
</html>