我正在尝试将一个混乱的字符串数组推送到我的范围变量,但是一些如何为重复的数组值抛出错误。这从未发生过。
以下是我的代码段。您可以检查控制台是否有错误:
var app = angular.module('ABCD', []);
app.controller('ABCDController', ['$scope',
function($scope) {
$scope.start_word = ['C', 'A', 'T'];
$scope.word = [
['C', 'A', 'T']
];
$scope.shuffle = function() {
var shuffle_word = Shuffle($scope.word[0]);
console.log("SHUFFLED VARIABLE: " + shuffle_word);
console.log("SCOPE VARIABLE: " + $scope.word);
$scope.word.push(shuffle_word);
};
}
]);
function Shuffle(o) {
for (var j, x, i = o.length; i; j = parseInt(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
return o;
};
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.9/angular.min.js"></script>
<div ng-app="ABCD">
<div ng-controller="ABCDController">
<button class="btn btn-primary" ng-click="shuffle()">Shuffle</button>
<p>START WORD: {{start_word}}</p>
<p ng-repeat="(key,value) in word">SHUFFLED WORD: {{value}}</p>
</div>
</div>
我的错误是,当我尝试将新的混洗值推入数组时,它会将所有值更改为新值。例如:
初始数组:
console.log($scope.word); OUTPUT: [['C','A','T']]
推后:
console.log($scope.word) OUTPUT: [['T','C','T'],['T','C','T']]
答案 0 :(得分:2)
您正在改变原始单词并创建两个相同的值。使用单词的临时副本,如下所示。编辑:This answer显示复制数组的技巧。
var app = angular.module('ABCD', []);
app.controller('ABCDController', ['$scope',
function($scope) {
$scope.start_word = ['C', 'A', 'T'];
$scope.word = [
['C', 'A', 'T']
];
$scope.shuffle = function() {
var tmpWord = $scope.word[0].slice(); // create a copy
var shuffle_word = Shuffle(tmpWord);
console.log("SHUFFLED VARIABLE: " + shuffle_word);
console.log("SCOPE VARIABLE: " + $scope.word);
$scope.word.push(shuffle_word);
console.log($scope.word);
};
}
]);
function Shuffle(o) {
for (var j, x, i = o.length; i; j = parseInt(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
return o;
};
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.9/angular.min.js"></script>
<div ng-app="ABCD">
<div ng-controller="ABCDController">
<button class="btn btn-primary" ng-click="shuffle()">Shuffle</button>
<p>START WORD: {{start_word}}</p>
<p ng-repeat="(key,value) in word">SHUFFLED WORD: {{value}}</p>
</div>
</div>
&#13;
答案 1 :(得分:0)
也许尝试在单词数组中有一个单词对象,如:
$scope.word[{num:0,word:'CAT'},{num:1,word:'ACT'}];
答案 2 :(得分:0)
您永远不会重置word
数组,因此每次对Shuffle()
的新调用都会添加到数组中,而不是仅仅替换数组的内容。
$scope.shuffle = function() {
var shuffle_word = Shuffle($scope.word[0]);
console.log("SHUFFLED VARIABLE: " + shuffle_word);
console.log("SCOPE VARIABLE: " + $scope.word);
$scope.word = []; //clear the previous array elements
$scope.word.push(shuffle_word);
};
或一个完整的片段(注意我将这个词改为“目录”)。
var app = angular.module('ABCD', []);
app.controller('ABCDController', ['$scope',
function($scope) {
$scope.start_word = ['C', 'A', 'T', 'A', 'L', 'O', 'G'];
$scope.word = [
['C', 'A', 'T', 'A', 'L', 'O', 'G']
];
$scope.shuffle = function() {
var shuffle_word = Shuffle($scope.word[0]);
console.log("SHUFFLED VARIABLE: " + shuffle_word);
console.log("SCOPE VARIABLE: " + $scope.word);
$scope.word = []; //clear the previous array elements
$scope.word.push(shuffle_word);
};
}
]);
function Shuffle(o) {
for (var j, x, i = o.length; i; j = parseInt(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
return o;
}
<!DOCTYPE html>
<html ng-app="ABCD">
<head>
<meta charset="utf-8" />
<title>AngularJS Plunker</title>
<script>document.write('<base href="' + document.location + '" />');</script>
<link rel="stylesheet" href="style.css" />
<script data-require="angular.js@1.3.x" src="https://code.angularjs.org/1.3.14/angular.js" data-semver="1.3.14"></script>
<script src="app.js"></script>
</head>
<div ng-app="ABCD">
<div ng-controller="ABCDController">
<button class="btn btn-primary" ng-click="shuffle()">Shuffle</button>
<p>START WORD: {{start_word}}</p>
<p ng-repeat="(key,value) in word ">SHUFFLED WORD: {{value}}</p>
</div>
</div>
</html>