Question

我正在尝试创建一个字母金字塔。

我的代码编译，最初有效，但在要求用户输入字母的初始提示后不会打印。这是我的代码目前的样子：

  intmain(void {
    char letter = 'A';
    char display;
    char output;
    int row;
    char spaces = ' ';

    printf ("Please enter a lowercase letter!");
    scanf ("%c", &letter);

    while ((letter < 96) || (letter > 122)) {
      printf ("That's not lowercase.");
      scanf ("%c", &letter);
    }

    else if ((letter > 96) || (letter < 122)) {
      while (1) {
        letter = letter - 32;
        printf ("%c", letter -1);
        printf ("\n\n");
        spaces = letter - 1;
        putchar = (spaces);
        letter++
        spaces++
      }
    }
    return 0;
  }
}

最终结果应如下所示。假设用户输入了E：

----------A
---------ABA
--------ABCBA
-------ABCDCBA
------ABCDEDCBA

因此，输入的字母将是金字塔底部的中心字母。

Answer 1

尝试一下，对我来说，它像这样：

#include <iostream>
#include <string>

char initialCharacter = 'A';
char characterToPrintTo = 'J';
int levels;

void printSpaces(int n)
{
    int i;
    for(i = 0; i < n; i++)
    {
        std::cout<<" ";
    }
}

int main()
{
    levels = characterToPrintTo - initialCharacter + 1;
    int numberOfCharacters = 2 * levels - 1;
    int maxChar, diff;
    for(int level = 1; level <= levels; level++)
    {
        maxChar = 2 * level - 1;
        if(maxChar < numberOfCharacters)
            diff = numberOfCharacters - maxChar;
        else diff = 0;
        printSpaces(diff/2);
        for(int i = 0; i < maxChar; i++)
        {
            if(i < maxChar / 2 + 1)
                std::cout<< (char) (initialCharacter + i);
            else
                std::cout<< (char) (initialCharacter + maxChar - i - 1);
        }
        printSpaces(diff/2);
        std::cout<<std::endl;
    }
    return 0;
}

这是输出：

         A
        ABA
       ABCBA
      ABCDCBA
     ABCDEDCBA
    ABCDEFEDCBA
   ABCDEFGFEDCBA
  ABCDEFGHGFEDCBA
 ABCDEFGHIHGFEDCBA
ABCDEFGHIJIHGFEDCBA

Answer 2

#include <iostream>
#include <string>

int main()
{
    std::string letters{};

    std::cout << "Enter a string of letters to create a Letter Pyramid from it: ";
    getline(std::cin, letters);

    size_t num_letters = letters.length();

    int position {0};

    // for each letter in the string
    for (char c: letters) {

        size_t num_spaces = num_letters - position;
        while (num_spaces > 0) {
            std::cout << " ";
            --num_spaces;
        }

        // Display in order up to the current character
        for (size_t j=0; j < position; j++) {
            std::cout << letters.at(j);
        }

        // Display the current 'center' character
        std::cout << c;

        // Display the remaining characters in reverse order
        for (int j=position-1; j >=0; --j) {
            // You can use this line to get rid of the size_t vs int warning 
            auto k = static_cast<size_t>(j);
            std::cout << letters.at(k);
        }

        std::cout << std::endl; // Don't forget the end line
        ++position;
    }

    return 0;
}

Answer 3

#include<iostream>
#include<string>
using namespace std;
int main(){
    string s;
    getline(cin,s);
    for(int i=0;i<s.length();i++){
        int spaces=s.length()-i-1;
        for(;spaces>0;spaces--){
            cout<<" ";
        }
        for(int j=0;j<=i;j++){
            cout<<s.at(j);
        }
        for(int k=i-1;k>=0;k--){
            cout<<s.at(k);
        }
        cout<<endl;
    }

return 0;
}

Answer 4

一旦你意识到这封信只是数字，这个问题就很容易了。您可以像任何其他数字一样添加和减去它们。

int main(int argc, char* argv[]) {
  char letter = 0;
  cout << "Enter a letter between A and Z";
  cin >> letter;
  cout << endl;

  for (int i = 'A'; i <= letter; i++) {
    for (int j = 'A'; j < i; j++)
      cout << (char)j;
    while (j >= 'A') {
      cout << (char)j;
      j--;
    }
    cout << endl;
  }
  return 0;
}

如何创建字母金字塔？

4 个答案: