当我在ActionScript中绘制矩形等时,使用Flash Player的绘图API(即Graphics
类),是在形状的外部还是内部绘制的该形状的边界线?例如,下列哪个图正确地描绘了在自定义组件中绘制内容区域边框的矩形?
我看了documentation for the Graphics
class,找不到任何提示。
答案 0 :(得分:2)
我写了一个简短的测试,使用固定大小的自定义组件,绘制一些线作为参考,然后在白色背景上绘制一个30像素宽边框的矩形。这就是它的样子,见下面的代码:
因此,参考问题中的图片,第二个图(“居中”)正确描绘了Flash Player绘制的方式。
还要注意内线(45像素)是如何在矩形内部,而外线(15像素)与矩形的外部边界对齐。
这是测试应用程序的代码:
<?xml version="1.0"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" xmlns:test="*">
<test:TestCanvas horizontalCenter="0" verticalCenter="0" id="canvas" />
</mx:Application>
这是TestCanvas
组件:
public class TestCanvas extends UIComponent
{
public function TestCanvas()
{
super();
}
override protected function measure():void
{
super.measure();
this.measuredWidth = this.minWidth = 300;
this.measuredHeight = this.minHeight = 300;
}
override protected function updateDisplayList(w:Number, h:Number):void
{
super.updateDisplayList(w, h);
this.graphics.clear();
this.graphics.lineStyle(undefined);
this.graphics.beginFill(0xffffff);
this.graphics.drawRect(0, 0, w, h);
this.graphics.endFill();
this.graphics.lineStyle(0, 0xff0000, 0.5);
this.graphics.moveTo(0, 15);
this.graphics.lineTo(300, 15);
this.graphics.moveTo(0, 45);
this.graphics.lineTo(300, 45);
this.graphics.moveTo(15, 0);
this.graphics.lineTo(15, 300);
this.graphics.moveTo(45, 0);
this.graphics.lineTo(45, 300);
this.graphics.lineStyle(0, 0xff0000, 0.75);
this.graphics.moveTo(0, 30);
this.graphics.lineTo(300, 30);
this.graphics.moveTo(30, 0);
this.graphics.lineTo(30, 300);
this.graphics.lineStyle(30, 0x0000ff, 0.25, false, "normal", null, JointStyle.MITER);
this.graphics.drawRect(30, 30, 240, 240);
}