Question

我有两张桌子

tbl_contact

contactID identity(1,1) not null,
contactname varchar(100)

tbl_l_contact_fund

l_contact_fund_id identity(1,1) not null,
contactID int FK to tbl_contact (contactID),
fundID int

我的 tbl_contact 表中有重复的联系人姓名，他们已经链接到 tbl_l_contact_fund

我想查询将所有重复联系人名称的关联从一个ID移到tbl_contact中的其他ID，并删除重复的联系人。我可以获得删除dup的最佳方法吗？谢谢！

例如：输入

tbl_contact

contactID  ContactName

1           Manoj 
2           Manoj
3           Rahul
4           Ajay
5           Rahul
6           Ajay

tbl_l_contact_fund

l_contact_fund_id contactID  fundID

1                   1           1 
2                   2           2
3                   1           3
4                   4           1
5                   6           2
6                   5           1

最终输出：

tbl_contact

contactID  ContactName

1           Manoj 
3           Rahul
4           Ajay

tbl_l_contact_fund

l_contact_fund_id contactID  fundID
1                   1           1 
2                   1           2
3                   1           3
4                   4           1
5                   4           2
6                   5           1

Answer 1

他的遗嘱将使用CTE

WITH crows AS (
     SELECT MIN(contactID) contactID, ContactName 
     FROM tbl_contact 
     GROUP BY ContactName
)
UPDATE tbl_l_contact_fund 
    SET contactID = (SELECT ContactID 
                                            FROM crows cr 
                                            WHERE ContactName in 
            (SELECT ContactName 
             FROM tbl_contact 
             WHERE ContactID = a.contactID))
FROM tbl_l_contact_fund a
GO
DELETE tbl_contact WHERE ContactID NOT IN (SELECT MIN(contactID) contactID 
                                           FROM tbl_contact GROUP BY ContactName)

或者您可以直接更新

UPDATE tbl_l_contact_fund 
        SET contactID = (SELECT MIN(ContactID) 
                         FROM tbl_contact cr 
                         WHERE ContactName in 
            (Select ContactName 
             FROM tbl_contact 
             WHERE ContactID = a.contactID))
FROM tbl_l_contact_fund a
GO
DELETE tbl_contact WHERE ContactID NOT IN (SELECT MIN(contactID) contactID 
                                            FROM tbl_contact GROUP BY ContactName)

Answer 2

这里你去找完整的sql

       UPDATE a 
SET a.contactid = c.contactid
FROM tbl_l_contact_fund a inner join
tbl_contact b on a.contactid = b.contactid
inner join (
SELECT * FROM tbl_contact a
where a.contactid in (SELECT min(b.contactid) 
                   FROM tbl_contact b 
                   WHERE b.contactname = a.contactname)
                   ) c
                   on c.contactname = b.contactname

    DELETE from tbl_contact a
    where a.contactid not in (SELECT min(b.contactid) 
                       FROM tbl_contact b 
                       WHERE b.contactname = a.contactname)

Answer 3

低于概念。

Update tbl_l_contact_fund tt
JOin
(
 Select realId, id, name from tbl_contact ac
  JOIN 
   (select min(Id) realId, name from tbl_contact    group by Name) dt 
        on dt.Name=ac.Name
) ot on ot.id=tt.id

Set tt.id=ot.realid

Answer 4

＆＃13;

DELETE A 
  FROM tbl_contact A 
  INNER JOIN tbl_l_contact_fund B ON A.contactID = B.contactID

＆＃13;

删除sql server中的重复项

4 个答案: