我有一个简单的文件上传,我希望使用href包含在jquery选项卡中。不幸的是,它在标签中打破了。
代码如下。如果我注释掉$(“#tabs”)。tabs();在包含代码中,它有效;如果没有,则不会发生文件上传。
包含在名为upload.html的文件中的文件上传代码如下:
<html>
<body>
<form name="registration" action="../php/recordInteraction.php" method="post"
accept-charset="utf-8" target="_self" enctype="multipart/form-data" >
<div>
<input type="file" name="fileToUpload" id="fileToUpload" >
<p><label for="submit"> Hi</label>
<input type="submit" name="submit" id="submit" value="Upload" >
</p>
</div>
</form>
</body> </html>
包含jquery代码small.html是:
<html lang="en">
<head>
<meta charset="utf-8">
<link rel="stylesheet" href="//code.jquery.com/ui/1.11.2/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.11.2/jquery-ui.js"></script>
<script>
$(function() {
$( "#tabs" ).tabs();
});
</script>
</head>
<body>
<div id="tabs" >
<ul>
<li><a id="upload" href="upload.html">Upload</a></li>
</ul>
</div>
</body>
</html>
答案 0 :(得分:0)
这是一个简单的jQuery解决方案。单击链接后,jQuery会单击文件上载按钮。
jQuery被评论。
$('#uploadButton').click(function() { // when the tab is clicked
$('#fileToUpload').click(); // pretend the file input was clicked
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<html>
<body>
<a href="#" id="uploadButton">Browse for files</a>
<br/><br/>
<form name="registration" action="../php/recordInteraction.php" method="post" accept-charset="utf-8" target="_self" enctype="multipart/form-data">
<div>
<input type="file" name="fileToUpload" id="fileToUpload">
<p>
<label for="submit">Hi</label>
<input type="submit" name="submit" id="submit" value="Upload">
</p>
</div>
</form>
</body>
</html>
答案 1 :(得分:0)
<html>
<body>
<a href="#" id="uploadButton">Browse for files</a>
<br/><br/>
<form name="registration" action="../php/recordInteraction.php" method="post"
accept-charset="utf-8" target="_self" enctype="multipart/form-data" **id="fileSubmitForm"**>
<div>
<input type="file" name="fileToUpload" id="fileToUpload" >
<p><label for="submit"> Hi</label>
<input type="submit" name="submit" id="submit" value="Upload" >
</p>
</div>
</form>
</body> </html>
$('#uploadButton').click(function() { // when the tab is clicked
$('#fileSubmitForm').submit(); // pretend the file input was clicked
});