Question

如何在XNA / Monogame中获得显示分辨率？我在我的显示器上尝试了这些（1600x900）：

下面给我800,600

//1.
GraphicsDevice.DisplayMode.Width
GraphicsDevice.DisplayMode.Height

//2.
GraphicsDeviceManager graphics = new GraphicsDeviceManager(this);
graphics.GraphicsDevice.DisplayMode.Width
graphics.GraphicsDevice.DisplayMode.Height

//3.
GraphicsAdapter.DefaultAdapter.CurrentDisplayMode.Width
GraphicsAdapter.DefaultAdapter.CurrentDisplayMode.Height

//4.
foreach (DisplayMode dm in GraphicsAdapter.DefaultAdapter.SupportedDisplayModes)
{
    Console.WriteLine(dm.Width);
    Console.WriteLine(dm.Height);
}

Answer 1

_ScreenWidth = System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width;
_ScreenHeight = System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height;

额外引用：System.Drawing，System.Windows.Forms

Answer 2

如果应用程序以全屏模式启动，则可能有效：

Vector2 resolution = new Vector2(GraphicsDevice.Viewport.Width,GraphicsDevice.Viewport.Height);

如何获得显示分辨率（屏幕尺寸）？

2 个答案: