Question

我正在研究一个将十进制输入转换为十六进制等效项的程序。我计划使用矢量系统地收集值，然后反向吐出它们（因此以十六进制形式）。但是我遇到了很多问题。所有输入直到16按预期工作，然后事情变得奇怪。输入16会导致系统输出笑脸，输入18个结果导致2个不同颜色的笑脸，23导致系统发出蜂鸣声。

这应该是一个相对简单的代码，它只是以我从未见过的方式表现出来！希望这些信息有帮助

编辑：我知道std :: hex函数，虽然这是针对一个类而且我们不允许使用它unfortunatley。

#include <iostream>
#include <string>
#include <vector>
#include <iomanip>

using  namespace std;

int main(){

int input, tester = 0, switchStuff, county = 0, remainderCount = 1, inputCount, remainder = 1, remainderCount2, inputCount2;
string stopGo;
char remainderLetter;

do{

   while (tester != 1){
  cout << "Enter the number you would like to convert to Hex format: ";
  cin >> input;
  if (cin.fail()){                     //check if user input is valid
     cout << "Error: that is not a valid integer.\n";
     cin.clear(); cin.ignore(INT_MAX, '\n');     //Clear input buffer
     continue;  //continue skips to top of loop if user input is invalid, allowing another attempt
  }
  else{
     tester = 1;     //Tester variable allows loop to end when good value input
  }
 }

inputCount = input;

while(inputCount != 0){

  remainderCount = inputCount % 16;
  inputCount = (inputCount - remainderCount) / 16;
  county++;

   }

vector<string>userInfo(county);

inputCount2 = input;

for (int i = 0; county > i; i++){

  remainderCount2 = inputCount2 % 16;
  inputCount2 = (inputCount2 - remainderCount2) / 16;

  if (remainderCount2 == 10){
     remainderLetter = 'A';
  }
  else if (remainderCount2 == 11){
     remainderLetter = 'B';
  }
  if (remainderCount2 == 12){
     remainderLetter = 'C';
  }
  else if (remainderCount2 == 13){
     remainderLetter = 'D';
  }
  if (remainderCount2 == 14){
     remainderLetter = 'E';
  }
  else if (remainderCount2 == 15){
     remainderLetter = 'F';
  }

  if (remainderCount2 >= 10){
     userInfo[i] = remainderLetter;
  }
  else{
     userInfo[i] = remainderCount2;
  }


}

cout << "The result in Hexadecimal format is: ";    

for (int i = 0; i < county; i++)
  cout << userInfo[i];

cout << endl << "Would you like to continue? (Enter Yes/No): ";     //Check whether to continue or not
cin >> stopGo;
cout << endl;

tester = 0;

}while ((stopGo.compare("Yes") == 0) || (stopGo.compare("yes") == 0) || (stopGo.compare("y") == 0) || (stopGo.compare("Y") == 0));   //Leaves user with a range of ways to say 'yes'

cout << "Thank you for using this program!" << endl;

system("pause");
 }

Answer 1

尝试更改

userInfo[i] = remainderCount2;

到

userInfo[i] = remainderCount2 + '0';

（＆＃39;导致数字0,1，...与char＆＃39; 0＆＃39;，＆＃39; 1＆＃39;，...）

不同

顺便说一句，有一种简单的方法可以将dec转换为十六进制

std::string sDecimal[] = "155";
char xHex[50];
sprintf(xHex, "%X", atoi(sDecimal.c_str()));

十进制到十六进制程序

1 个答案: