Question

我做了一个非常简单的猜谜游戏。但我想计算用户在找到原始号码之前所做的尝试总数。这意味着一旦隐藏号码与用户输入相匹配，它就应该告诉用户赢得了多少号码。

这是我的代码：

package guessinggame;

import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int hiddenNum = 10;

        Scanner input = new Scanner(System.in);


        while (true) {
            System.out.println("Enter a numebr by guessing: ");

            int guessedNum = input.nextInt();


            if (guessedNum == hiddenNum) {
                System.out.println("Congratulation! Your number is matched");

                System.exit(0);

            } else if (guessedNum < hiddenNum) {
                System.out.println("Not matched! Try a bigger number");


            } else if (guessedNum > hiddenNum) {
                System.out.println("Not matched! Try a smaller number");

            }    
        } 
    }    
}

Answer 1

银行足球比赛 } else if（guessedNum＆lt; hiddenNum）{ System.out.println（“不匹配！尝试更大的数字”）;

                //checking another condition
            } else if (guessedNum > hiddenNum) {
                System.out.println("Not matched! Try a smaller number");

            }    
        } 
    }    
}

Answer 2

试试这个：

public static void main(String[] args) {
    //storing the hidden number in a variable
    int hiddenNum = 10;
    //introducing the scanner class (for user input)
    Scanner input = new Scanner(System.in);
    //asking user to enter a random number

    int attempts = 0; // use as a counter

    while (true) {
        System.out.println("Enter a numebr by guessing: ");
        //Storing that into a variable
        int guessedNum = input.nextInt();

        attempts += 1;

        //Checking wheather the number is matched
        if (guessedNum == hiddenNum) {
            System.out.println("Congratulation! Your number is matched");
            //System.out.println("You have made total of " + attempts +" attempts to find the number!");
            //If matched number found, terminate the program
            System.exit(0);
            //checking another condition
        } else if (guessedNum < hiddenNum) {
            System.out.println("Not matched! Try a bigger number");

            //checking another condition
        } else if (guessedNum > hiddenNum) {
            System.out.println("Not matched! Try a smaller number");

        }

    } 
}

Answer 3

这个回复更适合http://codereview.stackexchange.com，但现在就这样了。

package guessinggame;

import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int hiddenNum = 10;
        int guessedNum = 0;
        Scanner input = new Scanner(System.in);

        boolean running = true;

        for (int i = 1; running; i++) {
            System.out.println("Enter a number to guess: ");
            guessedNum = input.nextInt();

            if (guessedNum == hiddenNum) {
                System.out.println("Congratulation! Your number is matched");
                System.out.println("You have made " + i + " to find the number!");
                running = false;
            } else if (guessedNum < hiddenNum) {
                System.out.println("Not matched! Try a bigger number");
            } else {
                System.out.println("Not matched! Try a smaller number");
            }    
        } 
    }    
}

代码的一些更改：

您应避免让while (true)和“随机”终止该程序。相反，我引入了boolean变量。它可以保留true或false的值。我在开始时将其设为true，然后在用户猜对的情况下将其设置为false。
我暂时删除了评论，通常在代码无法解释时应使用注释。例如，在for循环中使用它是一个很好的理由。（while循环在这里是更好的做法，我只想展示一个for循环。）
对于最后一个条件检查我删除了比较，无论是相等，更大还是更小。如果我们测试的是相同和更大的剩余部分，那么只剩下else那里。

如何跟踪用户输入数据的总尝试次数

3 个答案: