Question

我有下表

CREATE TABLE IF NOT EXISTS `eurojackpot` (
`datum_trekking` date NOT NULL,
`g1` tinyint(2) NOT NULL,
`g2` tinyint(2) NOT NULL,
`g3` tinyint(2) NOT NULL,
`g4` tinyint(2) NOT NULL,
`g5` tinyint(2) NOT NULL,
`b1` tinyint(2) NOT NULL,
`b2` tinyint(2) NOT NULL,
UNIQUE KEY `datum_trekking` (`datum_trekking`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

我执行下面的查询，它部分地给出了我正在寻找的结果集。

(SELECT g1 AS Nummer, count(*) AS Aantal
FROM  
( 
SELECT  g1 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  g2 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  g3 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  g4 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  g5 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
) y
GROUP BY  g1
ORDER BY Aantal
DESC
LIMIT 5
)
UNION
(SELECT b1 AS Bonus, count(*) AS aantal_b
FROM  
( 
SELECT  b1 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  b2 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
) z
GROUP BY  b1
ORDER BY aantal_b
DESC
LIMIT 5)

上述查询输出以下数据集：

+-------+--------+
+Nummer + Aantal +
+-------+--------+
+ 3     + 2      +
+ 22    + 2      +
+ 25    + 2      +
+ 41    + 2      +
+ 35    + 2      +
+ 4     + 3      +
+ 2     + 2      +
+ 8     + 2      +
+ 5     + 2      +
+ 3     + 1      +
+-------+--------+

我正在寻找的是一个输出如下的表：

+-------+--------+-------+----------+
+Nummer + Aantal + Bonus + aantal_b +
+-------+--------+-------+----------+
+ 3     + 2      + 4     + 3        +
+ 22    + 2      + 2     + 2        +
+ 25    + 2      + 8     + 2        +
+ 41    + 2      + 5     + 2        +
+ 35    + 2      + 3     + 1        +
+-------+--------+-------+----------+

什么是查询基本上是计算数字的出现次数并将其限制为具有最高出现次数的5个数字。它应该计算列g1到g5和b1到b2的数字。任何提示和技巧都非常感谢。我想我忽略了一些东西，但找不到最后一点让这个查询正常工作

Answer 1

执行Join而不是UNION：

SELECT yy.Nummer, yy.Aantal, zz.Bonus, zz.aantal_b
FROM
(
SELECT 
    g1 AS Nummer, 
    count(*) AS Aantal
FROM  ( 
    SELECT  g1 FROM  eurojackpot
        WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
    SELECT  g2 FROM  eurojackpot
        WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
    SELECT  g3 FROM  eurojackpot
        WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
    SELECT  g4 FROM  eurojackpot
        WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
    SELECT  g5 FROM  eurojackpot
        WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
) y
GROUP BY  g1
ORDER BY Aantal
DESC
LIMIT 5
) yy
JOIN
(SELECT b1 AS Bonus, count(*) AS aantal_b
FROM  
( 
SELECT  b1 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
    UNION  ALL 
SELECT  b2 FROM  eurojackpot
  WHERE datum_trekking >= DATE_SUB(NOW(), INTERVAL 1 MONTH)
) z
GROUP BY  b1
ORDER BY aantal_b
DESC
LIMIT 5) zz
ON y.g1 = z.b1

MySQL UNION 2设置了1个表的结果

1 个答案: