Question

我正在解码JSON数组，然后在将数据插入mysql之后使用foreach循环...但总是得到＆＃34;无法保存数据＆＃34; ！

请参阅下面的php脚本，了解我已尝试过的内容：

<?php

$objConnect = mysql_connect("localhost","","");
$objDB = mysql_select_db("test");

$raw_json = <<<EOT
{"data":[
{"PersonName":"first user","PersonEmail":"first@user.tld"},
{"PersonName":"second user","PersonEmail":"second@user.tld"}
]}
EOT;

// $raw_json = $_POST["allData"]; -- passing parameter

$json = json_decode($raw_json);
// echo json_encode($json); --- getting

foreach($json->data as $item){
// echo json_encode($item); --- getting
  $strPersonName = $item->PersonName;
// echo json_encode($strPersonName); --- getting
  $strPersonEmail = $item->PersonEmail;
// echo json_encode($strPersonEmail); --- getting

/*** Insert ***/
$strSQL = "insert into person (PersonName,PersonEmail)
values (
'".$strPersonName."',
'".$strPersonEmail."',
)
";

$objQuery = mysql_query($strSQL);
if(!$objQuery)
{
$arr['StatusID'] = "0";
$arr['Message'] = "Cannot save data";   
}
else
{
$arr['StatusID'] = "1";
$arr['Message'] = "Data stored successfully";
}
}

mysql_close($objConnect);
echo json_encode($arr);
?>

当我使用下面的PHP脚本时，我能够将数据存储到服务器，请检查：

<?php
$objConnect = mysql_connect("localhost","","");
$objDB = mysql_select_db("test");

$_POST["sPersonName"] = "demo";
$_POST["sPersonEmail"] = "deom@demo.tld";

$strPersonName = $_POST["sPersonName"];
$strPersonEmail = $_POST["sPersonEmail"];

/*** Insert ***/
$strSQL = "INSERT INTO person (PersonName, PersonEmail) 
    VALUES (
        '".$strPersonName."',
        '".$strPersonEmail."'
        )
    ";

$objQuery = mysql_query($strSQL);
if(!$objQuery)
{
    $arr['StatusID'] = "0"; 
    $arr['Message'] = "Cannot save data!";  
}
else
{
    $arr['StatusID'] = "1"; 
    $arr['Message'] = "Data stored successfully";   
}

/**
    $arr['StatusID'] // (0=Failed , 1=Complete)
    $arr['Error'] // Error Message
*/

mysql_close($objConnect);

echo json_encode($arr);
?>

那么可能是什么原因？为什么我无法将数据存储到mysql表，当我解码json数组？

Answer 1

您在最后一个值后面有逗号...

更改

$strSQL = "insert into person (PersonName,PersonEmail)
values (
'".$strPersonName."',
'".$strPersonEmail."',
)
";

到

$strSQL = "insert into person (PersonName,PersonEmail)
values (
'".$strPersonName."',
'".$strPersonEmail."'
)
";

PHP JSON Array解码并将数据存储到mysql

1 个答案: