Question

我需要将行转换为Oracle中的列。我是这种格式的数据：

Apple Orange Mango Banana
15    20     12    67

所需的结果是：

Fruit      Number
Apple      15
Orange     20
Mango      12
Banana     67

我使用Union来获得此结果，但这不是通用的。

SELECT ‘Apple’ AS Fruit, Apple AS Number FROM fruits_tbl UNION
SELECT ‘Orange’, Orange FROM fruits_tbl UNION
SELECT ‘Mango’, Mango FROM fruits_tbl UNION
SELECT ‘Banana’, Banana FROM fruits_tbl;

我想要标准程序来获得建议的输出。

更新：想出Pivot是正确的做法！

Answer 1

由于Oracle 11g（tab是您的表名）：

select * from tab 
UNPIVOT (num for fruit in (apple as 'apple', orange as 'orange', mango as 'mango', banana as 'banana'));

Oracle 10g：

with col_names as (
select 'apple' fruit from dual
union all select 'orange' from dual
union all select 'mango' from dual
union all select 'banana' from dual
)
select c.fruit, 
       case c.fruit       
          when  'apple' then t.apple          
          when  'orange' then t.orange          
          when  'mango' then t.mango          
          when  'banana' then t.banana          
       end as num
from tab t
cross join col_names c;

将垂直输入数据转换为Oracle中的水平输出

1 个答案: