Question

请建议在连续找到的mspaces中保留最大值mspace [如果连续找到文本包含的元素[mspace]]，有时可能会出现其他元素，如mrow会出现，在这种情况下连续文本只包含要考虑的空格。请与我联系并提供评论以便快速审核。

输入XML：

    <article>

<math>
    <mspace>3</mspace>
    <mrow>
        <mspace>3</mspace>
        <mspace>2</mspace>
        <mo>(</mo>
        <mo>+</mo>
        <mo>)</mo>
        <mspace>3</mspace>
   </mrow>
    <mspace>9</mspace>
</math>

<math>
    <mo>[</mo>
    <mrow>
    <mspace>3</mspace>
    <mspace>2</mspace>
    <mspace>3</mspace>
    <mtext>log</mtext>
    <mn>3</mn>
    <mspace>2</mspace>
    </mrow>
    <mspace>2</mspace>
</math>

<math>
    <mspace>3</mspace>
    <mspace>3</mspace>
    <mn>4</mn>
    <mo>-</mo>
    <mi>a</mi>
    <mspace>2</mspace>
</math>


</article>

XSLT：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="@*|node()">
    <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>

<xsl:template match="mspace">
    <xsl:variable name="var1" select="following::text()[normalize-space(.)!=''][1][generate-id(ancestor::math)=generate-id(current()/ancestor::math)]"/>
    <xsl:variable name="var2" select="preceding::text()[normalize-space(.)!=''][1][generate-id(ancestor::math)=generate-id(current()/ancestor::math)]"/>
    <xsl:variable name="var1a" select="following::text()[normalize-space(.)!=''][2][generate-id(ancestor::math)=generate-id(current()/ancestor::math)]"/>
    <xsl:variable name="var2a" select="preceding::text()[normalize-space(.)!=''][2][generate-id(ancestor::math)=generate-id(current()/ancestor::math)]"/>
    <xsl:variable name="vPresent" select="."/>
    <xsl:variable name="vMax" select="max(($var1, $var2, $var1a, $var2a, $vPresent))"/>

    <xsl:choose>
        <xsl:when test="$vPresent lt $var1 or $vPresent lt $var1a">
            <xsl:comment><xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy></xsl:comment>
        </xsl:when>
        <xsl:when test="$vPresent lt $var2 or $vPresent lt $var2a">
            <xsl:comment><xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy></xsl:comment>
        </xsl:when>
        <xsl:when test="$vPresent eq $var2 and $vPresent eq $var1a">
            <xsl:comment><xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy></xsl:comment>
        </xsl:when>

        <xsl:when test="not($vPresent eq $var2) and $vPresent eq $var1">
            <xsl:comment><xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy></xsl:comment>
        </xsl:when>

        <xsl:otherwise><xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy></xsl:otherwise>
    </xsl:choose>

</xsl:template>

</xsl:stylesheet>

必需的OutPut：

<?xml version="1.0" encoding="UTF-8"?><article>

<math>
    <!--3-->
    <mrow>
        <mspace>3</mspace>
        <!--2-->
        <mo>(</mo>
        <mo>+</mo>
        <mo>)</mo>
        <!--3-->
   </mrow>
    <mspace>9</mspace>
</math>

<math>
    <mo>[</mo>
    <mrow>
    <!--3-->
    <!--2-->
    <mspace>3</mspace><!--To be required-->
    <mtext>log</mtext>
    <mn>3</mn>
    <mspace>4</mspace><!--To be required-->
    </mrow>
    <!--2-->
</math>

<math>
    <!--3-->
    <mspace>3</mspace><!--To be required-->
    <mn>4</mn>
    <mo>-</mo>
    <mi>a</mi>
    <mspace>2</mspace><!--To be required-->
</math>


</article>

Answer 1

以下是我使用XSLT 2.0的建议：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="math[descendant::mspace]">
  <xsl:copy>
    <xsl:variable name="max-elements" as="element(mspace)*">
      <xsl:for-each-group select="descendant::*[not(*)]" group-adjacent="boolean(self::mspace)">
        <xsl:if test="current-grouping-key()">
          <xsl:sequence select="current-group()[. = max(current-group())][last()]"/>
        </xsl:if>
      </xsl:for-each-group>
    </xsl:variable>
    <xsl:apply-templates select="@*"/>
    <xsl:apply-templates select="node()">
      <xsl:with-param name="max-elements" select="$max-elements" tunnel="yes"/>
    </xsl:apply-templates>
  </xsl:copy>
</xsl:template>

<xsl:template match="mspace">
  <xsl:param name="max-elements" tunnel="yes"/>
  <xsl:choose>
    <xsl:when test=". intersect $max-elements">
      <xsl:next-match/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:comment select="."/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

</xsl:stylesheet>

它将您发布的样本转换为

<article>
   <math><!--3-->
      <mrow>
         <mspace>3</mspace>
         <!--2-->
         <mo>(</mo>
         <mo>+</mo>
         <mo>)</mo>
         <!--3-->
      </mrow>
      <mspace>9</mspace>
   </math>
   <math>
      <mo>[</mo>
      <mrow><!--3--><!--2-->
         <mspace>3</mspace>
         <mtext>log</mtext>
         <mn>3</mn>
         <!--2-->
      </mrow>
      <mspace>2</mspace>
   </math>
   <math><!--3-->
      <mspace>3</mspace>
      <mn>4</mn>
      <mo>-</mo>
      <mi>a</mi>
      <mspace>2</mspace>
   </math>
</article>

如果连续与其他mspace一起找到，如何保留最大值mspace

1 个答案: