Question

我需要像以下结构一样的唯一记录的计数

DATE      | STATUS |  EMPLOYEE|UNIQUEDATE|UNIQUESTATUS|UNIQUEEMPLOYEE
20-1-2013   active    John          7         3             2
20-1-2013   active    John          7         3             2
20-1-2013   active    Kyle          7         3             1
20-1-2013   inactive  mohan         7         4             1
20-1-2013   inactive  subbu         7         4             3
20-1-2013   inactive  subbu         7         4             3
20-1-2013   inactive  subbu         7         4             3

计数基于生成的输出值

我尝试了这个查询：

select DATE,STATUS,EMPLOYEE,COUNT(DATE) as DATECOUNT,COUNT(STATUS ) as DATESTATUS ,COUNT(EMPLOYEE) as DATEEMPLOYEE from dailyincome group by DATE,STATUS,EMPLOYEE

但所有三列的计数都相同。

Answer 1

试试这个：

select DATE,STATUS,EMPLOYEE,
  COUNT( DISTINCT DATE) as DATECOUNT,
  COUNT( DISTINCT STATUS ) as DATESTATUS ,
  COUNT( DISTINCT EMPLOYEE) as DATEEMPLOYEE 
from dailyincome group by DATE,STATUS,EMPLOYEE

我无法访问您的数据，因此无法测试，但是＆＃34; distinct＆＃34; COUNT（）函数中的关键字应该可以满足你的需要。我们可能需要添加GROUP BY子句

mysql：如何获取具有多个groupby的唯一记录的计数

1 个答案: