我正在尝试创建一个使用AES 256加密的应用程序。不幸的是，我无法让它发挥作用。也许我没有完全理解crpytographic逻辑。
所以它正在工作，但据我所知，哈希包含密码。但如果我更改密码输出是相同的。所以似乎CryptEncrypt忽略了哈希。
有人可以帮助我吗？
提前致谢！
这是我的代码：
if ( !CryptAcquireContext( &hProv, NULL, MS_ENH_RSA_AES_PROV, PROV_RSA_AES, CRYPT_VERIFYCONTEXT ) )
{
printf( "\nCryptAcquireContext failed %d", GetLastError() );
return;
}
if ( !CryptImportKey( hProv, ( const LPBYTE )&keyBlob, sizeof( keyBlob ), 0, CRYPT_EXPORTABLE, &hPubKey ) )
{
printf( "\nCryptImportKey failed %d", GetLastError() );
return;
}
if ( !CryptCreateHash( hProv, CALG_SHA_256, 0, 0, &hHash ) )
{
printf( "Error %x during CryptCreateHash!\n", GetLastError() );
return;
}
if ( !CryptHashData( hHash, ( PBYTE )wszPassword, cbPassword, 0 ) )
{
printf( "Error %x during CryptHashData!\n", GetLastError() );
return;
}
//if ( !CryptDeriveKey( hProv, CALG_AES_256, hHash, CRYPT_EXPORTABLE, &hKey ) )//hKey
//{
// printf( "Error %x during CryptDeriveKey!\n", GetLastError() );
// return;
//}
if ( !CryptSetKeyParam( hPubKey, KP_IV, ivData, 0 ) )
{
printf( "\nCryptSetKeyParam failed %d", GetLastError() );
return;
}
DWORD size = ( DWORD )strlen( StringToEncrypt ) / sizeof( char );
//printf( "\nLength of string to encrypt = %d\n\n", size );
if ( !CryptEncrypt( hPubKey, hHash, TRUE, 0, ( LPBYTE )StringToEncrypt, &size, ( size / 16 + 1 ) * 16 ) )
{
printf( "\nCryptEncrypt failed %d", GetLastError() );
int a = GetLastError();
switch ( a )
{
case NTE_BAD_HASH_STATE: printf( "NTE_BAD_HASH_STATE" ); break;
case NTE_BAD_HASH: printf( "NTE_BAD_HASH" ); break;
}
return;
}