将字符串与字符串元素数组进行比较

Question

所以，我想从字符串到字符串数组进行比较

String [] string = new String [10];
string [1] = "pencil";
string [2] = "pen";
string [3] = "eraser";

如何将字符串与上面的字符串数组进行比较？

Answer 1

更快捷的方法是使用此代码

if(Arrays.asList(string).contains(search_string))

Answer 2

如果我理解正确的话，写一个循环，迭代多个字符串（示例数组）并与src字符串相等。

String [] string = new String [10];
...
String src = ..;//src string

for(String string : string){
    if(src.equals(string)){
       //Equal
    }
}

Answer 3

尝试使用：

for (int i = 0; i < string.length; i++) {
    if (ch.equals(string[i])) { // ch is the string to compare
    System.out.println("equal");//or whatever your action is
    }
}

修改

如果您要做的是验证搜索到的字符串是否出现在字符串[i]中，您可以尝试：

string[0] = "pentagon";
string[1] = "pencil";
string[2] = "pen";
string[3] = "eraser";
string[4] = "penny";
string[5] = "pen";
string[6] = "penguin";
string[7] = "charp";
string[8] = "charpen";
string[9] = "";
String ch = "pen";

然后测试数组元素是否包含搜索的字符串：

for (int i = 0; i < string.length; i++) {
    if (string[i].indexOf(ch) != -1) {
    System.out.println(string[i]+" contains "+ch);
    } else
    System.out.println(string[i]+" doesn't contain "+ch);
}

编辑2：

int i=0;
Boolean found=false;
while(i < string.length && !found) {
    if (string[i].indexOf(ch) != -1) {
    found=true;
    }
 i++;
}
if(found){
system.out.println(ch+" is found");
}