我需要获取第二个<Item>
节点下的<Folder>
个节点列表。如果我使用以下XML源代码和C#代码,则将FolderNode设置为正确的节点(第二个<Folder>
节点),但将ItemsList设置为文件中每个<Item>
的集合,包括第一文件夹节点。因此,ItemsList包含5个项而不是3个。
XML来源:
<?xml version="1.0" encoding="UTF-8"?>
<MMM xmlns="http://some.url.com/2.0">
<Document>
<open>1</open>
<Folder>
<name>Folder_1_Data</name>
<Item>
<description>Folder 1 Item 1</description>
</Item>
<Item>
<description>Folder 1 Item 2</description>
</Item>
</Folder>
<Folder>
<name>Folder_2_Data</name>
<Item>
<description>Folder 2 Item A</description>
</Item>
<Item>
<description>Folder 2 Item B</description>
</Item>
<Item>
<description>Folder 2 Item C</description>
</Item>
</Folder>
</Document>
</MMM>
C#代码:
var doc = new XmlDocument();
doc.Load("Import.xml");
var nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("abc", "http://some.url.com/2.0");
var xnlNodes = doc.SelectNodes("//abc:Document", nsmgr);
var FolderNode = doc.SelectNodes("//abc:Folder", nsmgr).Item(1);
var ItemsList = FolderNode.SelectNodes("//abc:Item", nsmgr);
//Loop through each item in the 2nd folder node
//and pull out the description of each item.
答案 0 :(得分:1)
您只需添加一个前导.
即表示XPath与当前FolderNode
相关:
var ItemsList = FolderNode.SelectNodes(".//abc:Item", nsmgr);
//^notice this dot
由于<Item>
节点是<Folder>
节点的直接子节点,您也可以这样做:
var ItemsList = FolderNode.SelectNodes("abc:Item", nsmgr);
//without symbols at the beginning which..
//^.. will return only direct children nodes
或者这样:
var ItemsList = FolderNode.SelectNodes("./abc:Item", nsmgr);
//^using single slash which also return..
//.. only direct children nodes