Question

请查看以下查询。

SELECT sub_words.idwords, words_inc.idArticle
(
    SELECT sub0.idwords, SUBSTRING_INDEX(GROUP_CONCAT(sub1.idwords), ',', 10) AS excl_words,        COUNT(sub1.idwords) AS older_words_cnt
    FROM words_learned sub0
    LEFT OUTER JOIN words_learned sub1
    ON sub0.userId = sub1.userId
    AND sub0.order < sub1.order
    WHERE sub0.userId = 1
    GROUP BY sub0.idwords
) sub_words
INNER JOIN words words_inc
ON sub_words.idwords = words_inc.idwords
LEFT OUTER JOIN words words_exc
ON words_inc.idArticle = words_exc.idArticle
AND FIND_IN_SET(words_exc.idwords, sub_words.excl_words)
WHERE words_exc.idwords IS NULL
ORDER BY older_words_cnt
LIMIT 100

这给出了错误

＃1064 - 您的SQL语法出错;查看与您的MySQL服务器版本对应的手册，以便在'SELECT sub0.idwords，SUBSTRING_INDEX（GROUP_CONCAT（sub1.idwords），'，'，10）AS exc'在第3行附近使用正确的语法

我单独检查了子查询，子查询中没有错误！这里发生了什么？

Answer 1

您错过了from关键字

SELECT sub_words.idwords, words_inc.idArticle
FROM
( ...

＃1064 - 您的SQL语法出错：此查询有什么问题？

1 个答案: