如何在由数字定义的特定点处拆分字符串?
例如,在字符串' 123456'中生成两个变量t1
和t2
。并将其拆分为字符 3 ,以便t1
的值为' 123' t2
的价值是' 456' ...
var s0 = '123456';
console.log(s1);//123
console.log(s2);//456
答案 0 :(得分:1)
你可以这样做。
var s0 = '123456';
var arr = s0.split('3');
var t1 = arr[0] + '3', t2 = arr[1];
答案 1 :(得分:1)
我建议:
var s0 = '123456',
t1 = s0.substring(0, s0.indexOf(3) + 1),
t2 = s0.substring(s0.indexOf(3) + 1);
参考文献:
答案 2 :(得分:1)
类似的东西:
var foo = '123456'
,bar = [foo.slice(0,3), foo.slice(3)];
//=> bar now ["123", "456"]
扩展String prototype
:
String.prototype.splitAt = function(n) {
return n && n < this.length
? [this.slice(0,n), this.slice(n)]
: this;
}
// usages
'123456'.splitAt(3); //=> ['123', '456']
'123456'.splitAt(2); //=> ['12', '3456']
'123456'.splitAt(12); //=> '123456'
'123456'.splitAt(); //=> '123456'
答案 3 :(得分:1)
如果你的意思是第3个字符:
var ch = 3;
var s0 = "123456";
var s1 = s0.substr(0,ch); // will be '123'
var s2 = s0.substr(ch); // will be '456'
答案 4 :(得分:0)
尝试
var s0 = "123456"
, s1 = s0.slice(0, 3); // first 3 characters in string , `123`
, s2 = s0.slice(- (s0.length - s1.length) ); // remainder of string , `456`(+)
console.log(s0, s1, s2)
答案 5 :(得分:-1)
var s = '123456';
var sos = 3;//number to split by
var t1 = '';
var t2 = '';
for (var i = 0; i < s.length; i++)
{
if (i<sos) {t1 += s[i];}
else {t2 += s[i];}
}
console.log('t1 = '+t1);
console.log('t2 = '+t2);