所以我想在我的android程序中发布这个api：http://www.idmypill.com/api/id/。这是我的service处理程序类：
public class ServiceHandler
{
static String response = null;
public final static int GET = 1;
public final static int POST = 2;
public ServiceHandler() {
}
/**
* Making service call
* @url - url to make request
* @method - http request method
* */
public String makeServiceCall(String url, int method) {
return this.makeServiceCall(url, method, null);
}
/**
* Making service call
* @url - url to make request
* @method - http request method
* @params - http request params
* */
public String makeServiceCall(String url, int method,
List<NameValuePair> params)
{
try {
// http client
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpEntity httpEntity = null;
HttpResponse httpResponse = null;
android.os.Debug.waitForDebugger();
// Checking http request method type
if (method == POST)
{
HttpPost httpPost = new HttpPost(url);
httpPost.setHeader("Content-type", "application/json");
// adding post params
if (params != null)
{
httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost);
} else if (method == GET) {
// appending params to url
if (params != null) {
String paramString = URLEncodedUtils
.format(params, "utf-8");
url += "?" + paramString;
}
HttpGet httpGet = new HttpGet(url);
httpResponse = httpClient.execute(httpGet);
}
httpEntity = httpResponse.getEntity();
response = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return response;
}
}
我得到的回应是：Response:(1990): > {"errors": null, "results": [], "success": false}
我调用服务处理程序的主要活动如下：
public class QueryAPI extends Activity
{
private ProgressDialog pDialog;
// URL to get contacts JSON
private static String url = "http://www.idmypill.com/api/id/api";
Bitmap pillPicture;
List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
Intent QueryAPI = getIntent();
pillPicture = (Bitmap) QueryAPI.getParcelableExtra("PillImage");
nameValuePair.add(new BasicNameValuePair("api_key", "AIzaSyAdxxOjmh_nx4dKP_uJhtKy3cr32jrs7C8"));
nameValuePair.add(new BasicNameValuePair("image", "pillPicture"));
new GetPillInfo().execute();
}
private class GetPillInfo extends AsyncTask<Void, Void, Void>
{
@Override
protected void onPreExecute()
{
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(QueryAPI.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected Void doInBackground(Void... arg0)
{
android.os.Debug.waitForDebugger();
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.POST, nameValuePair);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null)
{
try
{
JSONObject jsonObj = new JSONObject(jsonStr);
Log.d("JSON", jsonObj.toString());
} catch (JSONException e) {
e.printStackTrace();
}
} else
{
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
@Override
protected void onPostExecute(Void result)
{
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
}
}
}
网站给出的python示例如下：
# highly suggested to use the requests package
# http://www.python-requests.org/en/latest/
import requests
# read in the image and construct the payload
image = open("example.jpg").read()
data = {"api_key": "KH8hdoai0wrjB0LyeA3EMu5n4icwyOQo"}
files = {"image": open("example.jpg")}
# fire off the request
r = requests.post("http://www.idmypill.com/api/id/",
data = data,
files = files)
# contents will be returned as a JSON string
print r.content
我不熟悉Python并且对使用Http请求非常新，所以建议会很棒。
答案 0 :(得分：1)
api想要一个MultiPartEntity，其中text值为api_key，而file图片为image。
Android本身并不支持MultiPart上传，但您可以使用Apache's HTTP Library对其进行存档，这实际上是Android的HTTP库的更新版本，因为它们是相同的。
一旦安装了库，只需在gradle中添加依赖项，然后修改代码以获得类似的代码：
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.addTextBody("api_key", yourAPIKey);
builder.addBinaryBody("image", inputStream); // Flexible here, see below
httpPost.setEntity(builder.build());
httpResponse = httpClient.execute(httpPost);
.addBinaryBody()实际上有各种方式接收图片，您可以传递File InputStream或图片的完整byte[]数组。
答案 1 :(得分：0)
你没有返回任何结果。返回方法是Void。这就是你无法在Log中看到任何结果的原因。
将AsyncTask更改为
私有类GetPillInfo扩展了AsyncTask {
@Override
protected void onPreExecute()
{
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(QueryAPI.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected String doInBackground(String... arg0)
{
android.os.Debug.waitForDebugger();
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.POST, nameValuePair);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null)
{
try
{
JSONObject jsonObj = new JSONObject(jsonStr);
Log.d("JSON", jsonObj.toString());
} catch (JSONException e) {
e.printStackTrace();
}
} else
{
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
@Override
protected void onPostExecute(String result)
{
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
}
} }