Question

我正在尝试加入两个查询

查询1：

select ProposalTypeID 
from tblAssessment 
where AssessmentID = AssessmentID

查询2：

select AssessmentID 
from tblAssessmentVersion 
where AssessmentVersionID = 3

感谢您的指导，但我试图在存储过程中添加该查询以检索proposalTypeID并在我的存储过程中使用但它抱怨

SELECT 
    AssessmentEcosystemCreditID, AssessmentVersionID, 
    dbo.tblAssessmentEcosystemCredit.ManagementZoneID, 
    (SELECT ProposalTypeID 
     FROM tblAssessment 
     WHERE AssessmentID = (SELECT AssessmentID  
                           FROM tblAssessmentVersion 
                           WHERE AssessmentVersionID = dbo.tblAssessmentEcosystemCredit.AssessmentVersionID)) AS ProposalTypeID,
    CASE 
       WHEN SiteValueCurrentScore <= 17 AND (dbo.tblVegetationZone.EECID > 0 ) AND (ProposalTypeID=699) 
          THEN 0
          ELSE NumberOfCredits
    END AS NumberOfCreditst
FROM 
    dbo.tblAssessmentEcosystemCredit
INNER JOIN 
    dbo.tblVegetationType ON dbo.tblAssessmentEcosystemCredit.VegTypeID = dbo.tblVegetationType.VegTypeID 
INNER JOIN 
    dbo.tblManagementZone ON dbo.tblAssessmentEcosystemCredit.ManagementZoneID = dbo.tblManagementZone.ManagementZoneID 
INNER JOIN 
    dbo.tblVegetationZone ON dbo.tblVegetationZone.VegetationZoneID = dbo.tblManagementZone.VegetationZoneID
WHERE 
    dbo.tblAssessmentEcosystemCredit.AssessmentVersionID = @AssessmentVersionID

Answer 1

所以？

select ProposalTypeID 
from tblAssessment 
where AssessmentID in 
  (select AssessmentID 
   from tblAssessmentVersion 
   where AssessmentVersionID=3)

Answer 2

select ProposalTypeID 
from tblAssessment 
where AssessmentID = (select AssessmentID 
                      from tblAssessmentVersion 
                      where AssessmentVersionID = 3)

尝试加入两个查询并检索列

2 个答案: