Question

我正在尝试根据另外两个表（DMS_TEST_LOAD和TDCE_NE）更新表格（TDCE_NE_COMP）。知道下面的查询有什么问题吗？我一直在UPDATE语句中得到无用的“语法错误”。来自Access的错误。提前谢谢。

UPDATE DMS_TEST_LOAD AS DMS 
((INNER JOIN TDCE_NE_COMP AS COMP
ON COMP.[NAME] LIKE DMS.[Trunk Group Number (TGN)] AND COMP.[NE_COMP_TYPE_ID]=421)
INNER JOIN TDCE_NE AS NE ON NE.[ID]=COMP.[NE_ID] AND NE.[NAME]=DMS.[Office])
SET DMS.[Char Parm 1 (Trk Dir)] = COMP.[CHAR_PARM1];

Answer 1

不太确定SQL系统MS访问使用的是什么。但你可能想尝试这个

UPDATE DMS
SET DMS.[Char Parm 1 (Trk Dir)] = COMP.[CHAR_PARM1]
FROM DMS_TEST_LOAD AS DMS
 INNER JOIN TDCE_NE_COMP AS COMP
   ON COMP.[NAME] LIKE DMS.[Trunk Group Number (TGN)]
      AND COMP.[NE_COMP_TYPE_ID]=421
  INNER JOIN TDCE_NE AS NE
     ON NE.[ID]=COMP.[NE_ID] AND NE.[NAME]=DMS.[Office];

Answer 2

在MS Access中，您必须确保在连接中正确使用括号。我相信你是在追求以下目标：

UPDATE DMS
SET DMS.[Char Parm 1 (Trk Dir)] = COMP.CHAR_PARM1
FROM (DMS_TEST_LOAD AS DMS
  INNER JOIN TDCE_NE_COMP AS COMP 
    ON (COMP.NAME = DMS.[Trunk Group Number (TGN)]) AND (COMP.NE_COMP_TYPE_ID = 421)) 
  INNER JOIN TDCE_NE AS NE 
    ON (NE.Name = DMS.Office) AND (COMP.NE_ID = NE.ID)

注意我删除了LIKE并将其替换为=。您没有使用任何通配符，因此它甚至不能用作LIKE。如果您想使用LIKE，您可能正在寻找以下内容：

COMP.NAME LIKE "*" & DMS.[Trunk Group Number (TGN)] & "*"

Answer 3

这样的事情怎么样......

UPDATE DMS
SET [Char Parm 1 (Trk Dir)] = COMP.[CHAR_PARM1] 
FROM DMS_TEST_LOAD DMS
INNER JOIN TDCE_NE_COMP AS COMP
    ON COMP.[NAME] LIKE DMS.[Trunk Group Number (TGN)] 
    AND COMP.[NE_COMP_TYPE_ID]=421
INNER JOIN TDCE_NE AS NE 
    ON NE.[ID]=COMP.[NE_ID] 
    AND NE.[NAME]=DMS.[Office]

未经测试但重构为ANSI 92＆＃34;标准＆＃34; SQL

可以使用...

测试（实际上没有更新c）

SELECT [Char Parm 1 (Trk Dir)],  COMP.[CHAR_PARM1] 
FROM DMS_TEST_LOAD DMS
INNER JOIN TDCE_NE_COMP AS COMP
    ON COMP.[NAME] LIKE DMS.[Trunk Group Number (TGN)] 
    AND COMP.[NE_COMP_TYPE_ID]=421
INNER JOIN TDCE_NE AS NE 
    ON NE.[ID]=COMP.[NE_ID] 
    AND NE.[NAME]=DMS.[Office]

MS Access：具有多个连接的Update语句

3 个答案: