Mysql从复杂结果中选择随机行

Question

我有类似这样的选择：

SELECT TABLE_4.ID, TABLE_4.USERNAME, TABLE_4.PHOTO,

SELECT(COUNT(SOMETHING) FROM TABLE_1 WHERE ..) AS NUM_ALL
SELECT(COUNT(SOMETHING) FROM TABLE_1 WHERE ..) AS NUM_DONE
SELECT(COUNT(SOMETHING) FROM TABLE_2 WHERE ..) AS NUM_LIKES

SELECT(COUNT(SOMETHING) FROM TABLE_3 WHERE ..) AS FOLLOWING
SELECT(COUNT(SOMETHING) FROM TABLE_3 WHERE ..) AS FOLLOWERS

CASE WHEN...

FROM TABLE_4
LEFT JOIN...
LEFT JOIN...
LEFT JOIN...

WHERE <condition>

GROUP BY TABLE_4.ID LIMIT 1000;

假设此查询有5000个结果。我希望以随机顺序排列前1000个。我认为rand（）对于这个复杂而冗长的查询是不可能的。

你能帮我一把吗？

Answer 1

是的，你可以使用兰德。只需添加

... ORDER BY RAND() LIMIT 1000;

在您的查询结束时。无论查询多么完整，都会在最终结果被处理时应用RAND（）（EXPLAIN结果的第一行）。