Question

因此我尝试使用来自表单的多个参数进行查询以执行属性搜索方法。但我正在努力使用showResults方法，因为我不断获得Missing argument 1 for IndexController::showResults()。此外，我想确保如何搜索属性和类别之间的多对多关系。 categories[]是我表单中的选择倍数。

到目前为止，这是我的代码。

Route::get('buscar/propiedades', array('as' => 'search', 'uses' => 'IndexController@showResults'));
Route::post('buscar/propiedades', array('as' => 'search', 'uses' => 'IndexController@searchProperties'));

public function showResults($categories, $activity, $currency, $beds, $baths, $price)
{
    return View::make('front.results')
                ->with('properties', Property::join('category_property', 'properties.id', '=', 'category_property.property_id')
                    ->join('categories', 'category_property.category_id', '=', 'categories.id')
                    ->join('activities', 'activities.id', '=', 'properties.activity_id')
                    ->join('currencies', 'currencies.id', '=', 'properties.currency_id')
                    ->whereIn('categories.id', $categories)
                    ->orWhere('activities.id', '=', $activity)
                    ->orWhere('currencies.id', '=', $currency)
                    ->orWhere('properties.beds', '=', $beds)
                    ->orWhere('properties.baths', '=', $baths)
                    ->orWhere('properties.price', '=', $price)
                    ->paginate(6);
}

public function searchProperties()
{
    $validator = Validator::make(Input::all(), Property::$search_rules);

    // if the validator fails, redirect back to the form
    if ($validator->fails()) {
        return Redirect::to('/')
            ->withInput(); // send back the input (not the password) so that we can repopulate the form
    }else{
        $categories = Input::get('category_id');
        $activity = Input::get('activity_id');
        $currency = Input::get('currency_id');
        $beds = Input::get('beds');
        $baths = Input::get('baths');
        $price = Input::get('price');
    }

    $this->showResults($categories, $activity, $currency, $beds, $baths, $price);

    return Redirect::to('buscar/propiedades');
}

Answer 1

您的验证必须失败，这意味着您作为参数传递的变量未定义。

设置vars后设置调用方法，或设置vars并调用方法。

尝试：

public function searchProperties()
{
    $validator = Validator::make(Input::all(), Property::$search_rules);

    // if the validator fails, redirect back to the form
    if ($validator->fails()) {
        return Redirect::to('/')
            ->withInput(); // send back the input (not the password) so that we can repopulate the form
    }else{
        $categories = Input::get('category_id');
        $activity = Input::get('activity_id');
        $currency = Input::get('currency_id');
        $beds = Input::get('beds');
        $baths = Input::get('baths');
        $price = Input::get('price');

        $this->showResults($categories, $activity, $currency, $beds, $baths, $price);
    }

    return Redirect::to('buscar/propiedades');
}

在伪代码中，这将：

使用输入和规则数组
如果失败，则重定向到没有输入的根路由
如果它通过，它会将所有变量设置为等于输入，并使用这些变量作为参数调用showResults方法。

最后重定向到您的URI。

在搜索查询Laravel中缺少IndexController的参数1

1 个答案: