Question

我需要制作一份列表来打印月份以及是否已付款。

首先我创建一个包含月份名称的数组：

$month_names = array("January","February","March","April","May","June","July","August","September","October","November","December");

然后我列出了十二个月的列：非付费的付费0的值为1。所以我做了一个变量来知道它是否有偿：

if ($row['month1'] == '1') {
    $row['month1'] = 'Paid';
} else $row['month1'] = 'Non-Paid';

有更好的方法吗？

该列表只有两列：＆＃34;每月付款＆＃34;和＆＃34;状态＆＃34;。

而while或foreach应该是这样的：

echo '
    <li><a class="months">'$array[$month_names]=>$value'</a></li>
    <li><a class="status">'.$row['month1'].'</a></li>
    ';

我不确定，我怎么能这样做？

谢谢你！

Answer 1

如果我理解你，你就有这样的数组：

$rows = array(
    array('month' => 1, 'paid' => 0),
    array('month' => 2, 'paid' => 1),
    array('month' => 4, 'paid' => 0),
    array('month' => 5, 'paid' => 1),
    array('month' => 7, 'paid' => 1),
    array('month' => 8, 'paid' => 0),
);

在这种情况下，你可以做这样的事情

<ul class="rows">
    <?php foreach ($rows as $row): ?>
        <li><a href="#" class="month"><?php echo $month_names[$row['month']] ?></a></li>
        <li><a href="#" class="status"><?php echo $row['paid'] ? 'Paid' : 'Non-Paid' ?></a></li>
    <?php endforeach ?>
</ul>

这是理想的，但我注意到你的示例数组有一个month1键，所以如果你的数组有这个结构：month[0-9] = paid-status：

$rows = array(
    'month1' => 0,
    'month2' => 1,
    'month4' => 0,
    'month5' => 1,
    'month7' => 1,
    'month8' => 0,
);

然后你应该做这样的事情：

<ul class="rows">
    <?php foreach ($rows as $month => $status): ?>
        <!-- We replace all non-numeric caracters in the key of the element and then sustract one to match the zero base index -->
        <li><a href="#" class="month"><?php echo $month_names[ preg_replace('/[^0-9]/', '', $month) - 1 ] ?></a></li>
        <li><a href="#" class="status"><?php echo $status ? 'Paid' : 'Non-Paid' ?></a></li>
    <?php endforeach ?>
</ul>

Answer 2

您走在正确的轨道上，使您的逻辑与演示文稿分开。这是一件好事。对于您的问题，您可以检查所有月份值并将结果存储在另一个数组中（让我们称之为$paid），并按月份编号索引。然后，您使用$monthNames数组映射到$paid中的相应值。这将使您循环遍历$monthNames数组并创建HTML。

以下将满足您的需求：

<?php

$monthNames = array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November","December");
$paid = array(); //Placeholder for paid months.
$row = $result->fetch_array();  //Assuming MySQLi API (you are using that or PDO...I hope...)

for($i = 1; $i < 13; $i++) {
    $month = "month" . $i;
    if($row[$month] == 1) {
        $paid[] = "Paid";
    } else {
        $paid[] = "Not Paid";
    }
}

//Now make the HTML list

print("<ul>\n");
foreach($monthNames as $key => $month) {
    print('<li><a class="months">' . $month . '</a></li>' . "\n");
    print('<li><a class="status">' . $paid[$key] .'</a></li>' . "\n");
}
print("</ul>");

?>

输出将沿着（取决于DB数据）：

<ul>
<li><a class="months">January</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">February</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">March</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">April</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">May</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">June</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">July</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">August</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">September</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">October</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">November</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">December</a></li>
<li><a class="status">Paid</a></li>
</ul>

希望有所帮助！

php mysql打印月份和表格内容

2 个答案: