我是grails / extjs的新手我正在为我的团队开发基于Web的配置工具。我的问题是使用extjs的组合框我有三个远程combox(多对一hibernate mappng)。我使用hiddenName提交它value字段(这是数据库的id primay键)而不是它的显示字段,这是我通过将其渲染为json.some得到的名称,我怎么看,如果我选择不同于从db加载的diff索引并尝试更新它。它确实将它作为参数发送,但在保存grails的方法中它没有更新。
我想明白为什么? 我已经粘贴了combobox和grails方法的片段吗?
{
xtype : 'combo',
id:'cpsServerid',
fieldLabel : 'CpsServer',
name : 'cpsServer',
//hiddenId:'cpsID',
hiddenName:'cpsID',
store: cpsServerStore,
displayField:'NAME',
valueField:'ID',
editable:true,
typeAhead:true,
mode:'remote',
triggerAction:'all',
width:300,
autoScroll:true,
selected:name,
selectOnFocus:true},
GRAILS SAVE
def saveApplicationSubscription = {
println "saveApplicationSubscription, params = $params"
ApplicationSubscription subscription
if (params.id) {
subscription = ApplicationSubscription.get(params.id as int)
subscription.cpsServer = CpsServer.get(params.cpsID as int)
subscription.topic = params.topic
subscription.description = params.description
subscription.subscriberApplication = SubscriberApplication.get(params.subAppID as int)
subscription.outputQueue = OutputQueue.get(params.outputID as int)
bindData(subscription , params)
}
else {
params.id = 0
subscription = new ApplicationSubscription(params)
subscription.id = params.id as int
subscription.cpsServer = CpsServer.get(params.cpsID as int )
subscription.topic = params.topic
subscription.description = params.description
subscription.subscriberApplication = SubscriberApplication.get(params.subAppID as int)
subscription.outputQueue = OutputQueue.get(params.outputID as int)
// subscription.messageFormat = params.messageFormat
}
if (subscription.save()) {
log.info("Saved ApplicationSubscription $subscription")
render([success: true] as JSON)
}
else {
log.info("Failed to save ApplicationSubscription $subscription, errors = ${subscription.errors}")
render([success: false, errors: subscription.errors] as JSON)
}
}
我真的会提供任何帮助
答案 0 :(得分:0)
您是否在Firebug控制台选项卡中验证了您的POST看起来像您期望的那样?这将确认您的问题是否在客户端或服务器上。