Question

我已经开始使用ec2-12-34-567-89.us-west-2.compute.amazonaws.com的DNS开发了一个amazon-ec2实例。我在那里设置了一个安全组，其中type = HTTP，protocol = TCP，port range = 80，source = 0.0.0.0 /。我登录EC2实例并启动我的应用程序：

$ python3 run.py
 * Running on http://0.0.0.0:0/

然后使用浏览器我尝试打开：http://ec2-12-34-567-89.us-west-2.compute.amazonaws.com并获得＆＃34;无法连接＆＃34;消息。

我在这里缺少什么？

修改

使用端口80，它最终会像这样：

$ python3 run.py
 * Running on http://0.0.0.0:80/
Traceback (most recent call last):
  File "run.py", line 5, in <module>
    app.run(host="0.0.0.0", port=80)
  File "/opt/python/3.4.1/lib/python3.4/site-packages/flask/app.py", line 772, in run
    run_simple(host, port, self, **options)
  File "/opt/python/3.4.1/lib/python3.4/site-packages/werkzeug/serving.py", line 710, in run_simple
   inner()
  File "/opt/python/3.4.1/lib/python3.4/site-packages/werkzeug/serving.py", line 692, in inner
    passthrough_errors, ssl_context).serve_forever()
  File "/opt/python/3.4.1/lib/python3.4/site-packages/werkzeug/serving.py", line 486, in make_server
    passthrough_errors, ssl_context)
  File "/opt/python/3.4.1/lib/python3.4/site-packages/werkzeug/serving.py", line 410, in __init__
    HTTPServer.__init__(self, (host, int(port)), handler)
  File "/opt/python/3.4.1/lib/python3.4/socketserver.py", line 429, in __init__
    self.server_bind()
  File "/opt/python/3.4.1/lib/python3.4/http/server.py", line 133, in server_bind
    socketserver.TCPServer.server_bind(self)
  File "/opt/python/3.4.1/lib/python3.4/socketserver.py", line 440, in server_bind
    self.socket.bind(self.server_address)
PermissionError: [Errno 13] Permission denied

Answer 1

显然我需要以超级用户身份运行我的代码。

$ **sudo** python3 run.py
 * Running on http://0.0.0.0:80/

如何公开查看我在amazon-ec2上托管的网站？

1 个答案: