我创建了一个视图调用styles.cshtml,我想动态创建样式表。 什么是css内部代码块的正确形式? 下面是错误的代码块,这个例子的正确形式是什么。
@foreach (var column in Model.Tabs[i].MegaMenuColumns) //columns
{
if(column.Width || column.TextColor || column.BackgroundColor)
{
#column@(column.Id)
{
width: @(column.Width) ;
color: @(column.TextColor);
if(column.IsGradient)
{
background-image: -o-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
background-image: -moz-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
background-image: -webkit-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
background-image: -ms-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
background-image: linear-gradient(to bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
}
else
{
background: @(column.BackgroundColor);
}
}
}
}
答案 0 :(得分:0)
你必须告诉那里从纯文本的开始和形式开始剃刀代码。
@:
告诉它是纯文本而不是razor代码,并且@
或@(some code here)
telll它是c#代码块:
@foreach (var column in Model.Tabs[i].MegaMenuColumns)
{
if(column.Width || column.TextColor || column.BackgroundColor)
{
@:#column@(column.Id)
@:{
@:width: @(column.Width) ;
@:color: @(column.TextColor);
if(column.IsGradient)
{
@:background-image: -o-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
@:background-image: -moz-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
@:background-image: -webkit-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
@:background-image: -ms-linear-gradient(bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
@:background-image: linear-gradient(to bottom, @(column.BackgroundColor) 0%, @(column.BackgroundColorGradient) 100%);
}
else
{
@:background: @(column.BackgroundColor);
}
@:}
}
}