我有3个输入文件,我想在一个提交按钮表单事件onSubmit =""
中为3个输入文件进行javascript验证<form action="step2_crud_dev.php" method="post" enctype="multipart/form-data" class="form-horizontal" role="form" id="dataPribadi" >
<div>
<input type="file" name="fUpload1" id="fileUpload1"/>
<input type="file" name="fUpload2" id="fileUpload2"/>
<input type="file" name="fUpload3" id="fileUpload3"/>
</div>
<div>
<input type="submit" name="upload" value="upload" />
</div>
</form>
已编辑的代码 新的代码,但仍然可以保存
$(document).ready(function(){
$('#tbl_next').click(function(){
//alert('hello');
$('input[type="file"]').each(function(){
var thisFile = $(this);
var fileSize = thisFile[0].files[0].size;
var fileType = thisFile[0].files[0].type;
//alert(fileSize);
if(fileSize>1048576){ //do something if file size more than 1 mb (1048576)
alert(fileSize +" bites\n ukuran gambar terlalu besar");
return false;
}else{
switch(fileType){
case 'image/png':
case 'image/gif':
case 'image/jpeg':
case 'image/pjpeg':
alert("Acceptable image file!");
break;
default:
alert('Unsupported File!');
return false;
}
}
});
$('form#dataPribadi').submit();
});
});
答案 0 :(得分:0)
将提交按钮的类型更改为普通按钮,并使用onclick
作为id
使用upload
处理程序,
<form action="step2_crud_dev.php" method="post" enctype="multipart/form-data" class="form-horizontal" role="form" id="dataPribadi" >
<div>
<input type="file" name="fUpload1" id="fileUpload1"/>
<input type="file" name="fUpload2" id="fileUpload2"/>
<input type="file" name="fUpload3" id="fileUpload3"/>
</div>
<div>
<input type="button" id="upload" value="upload" />
</div>
</form>
并且您的点击事件处理程序应该是,
$(document).ready(function(){
$('#upload').click(function(){
alert('hello');
$('input[type="file"]').each(function(){
var thisFile = $(this);
var fileSize = thisFile[0].files[0].size;
alert(fileSize);
});
$('form#dataPribadi').submit();
});
});