问题描述:
修改这些文件以便能够以交互方式要求用户提供要显示的广告消息。用户键入要显示的消息并按ENTER键。接受用户输入的消息。显示用户请求作为广告消息的消息,在显示之间重复暂停1秒。
如果用户再次按下ENTER(在显示上一条消息时),程序应该询问用户是否有新的(已修改的)消息。用户键入新消息并按ENTER键。广告显示现在应该更改为显示新消息显示,重复显示之间暂停1秒。当用户输入n(不区分大小写)时退出程序。
如果我使用下面的代码,第一次输入消息时它正常工作,当我按Enter键时,重复打印消息会被正确中断,并提示我输入新消息。但是,当我单击输入时,由于主方法已完成,因此不会中断重复打印:
import java.util.Scanner;
class Advertisement extends Thread
{
private boolean done = false;
String message = "";
public void run()
{
Thread myThread = Thread.currentThread();
while (!isDone())
{
System.out.println("Please enter the advertisement message to be displayed
(enter 'n' to exit):");
Scanner sc2 = new Scanner(System.in);
message = sc2.nextLine();
if (message.equalsIgnoreCase("n"))
{
done = true;
System.out.println("User Stopped the Message Output");
continue;
}
while (!(myThread.isInterrupted()))
{
try
{
System.out.print("** " + message + " **");
myThread.sleep(1000);
}
catch (InterruptedException e)
{
System.out.println("Exception caught: " + e.getMessage());
break;
}
}
}
}// end of 'run()' ..
/**
* @return the done
*/
public boolean isDone()
{
return done;
}
}
import java.util.Scanner;
public class TestAdvt2
{
public static void main (String[] args)
{
Advertisement advt = new Advertisement();
advt.start();
Scanner sc = new Scanner(System.in);
String str = "start";
while (!((str.equals(""))))
{
str = sc.nextLine();
}
advt.interrupt();
}
}
如果我将main方法更改为包含while循环,则中断将完全停止工作。
import java.util.Scanner;
class TestAdvt
{
public static void main (String[] args)
{
Advertisement advt = new Advertisement();
advt.start();
Scanner sc = new Scanner(System.in);
boolean done = false;
while (done == false);
{
String str = "start";
while (!((str.equals(""))))
{
str = sc.nextLine();
}
done = advt.isDone();
advt.interrupt();
}
}
}
有关如何使其工作以便可以更改消息的任何建议将不胜感激。
珍
更新:
我能够使用您的建议来修复我的代码。我需要做一些清理并使用synchronized关键字而不是volatile关键字(这是老师想要的)。
这是固定代码:
import java.util.Scanner;
/**
*
* @author Jeanne Gaskill
*/
public class Advertisement2 extends Thread
{
private boolean done = false;
String message = "";
public void run()
{
Thread myThread = Thread.currentThread();
while (true)
{
while (!done)
{
System.out.println("\n\nPlease enter the advertisement message to be displayed "
+ "(type message or enter 'n' to exit):\n");
Scanner sc2 = new Scanner(System.in);
message = sc2.nextLine();
done = true;
System.out.println("\n");
if (message.equalsIgnoreCase("n"))
{
System.out.println("User Stopped the Message Output");
// Terminating
System.exit(0);
continue;
}
while (!(myThread.isInterrupted()))
{
try
{
System.out.print("** " + message + " **");
Thread.sleep(1000);
}
catch (InterruptedException e)
{
// System.out.println("Exception caught: " + e.getMessage());
done = false;
break;
}
}
}
}
}// end of 'run()' ..
/**
* @return done variable
*/
synchronized public boolean isDone()
{
return done;
}
/**
* @param done to set done variable
*/
synchronized public void setDone(boolean done)
{
this.done = done;
}
}
import java.util.Scanner;
public class TestAdvt
{
public static void main (String[] args)
{
Advertisement advt = new Advertisement();
advt.start();
Scanner sc = new Scanner(System.in);
while (true)
{
while (advt.isDone())
{
// main thread is listening
String str = sc.nextLine();
// check for new line
if (str.equals(""))
{
advt.interrupt();
}
advt.setDone(false);
}
}
}
}
@Jigar
再次感谢!
答案 0 :(得分:0)
代码中的几件事
只有在广告话题没有收听时以及刚刚打印时,你才需要继续收听主要内容
您需要将volatile
用于标志变量
正确控制旗帜
摘要this is the code you need,格式,清理,在您身边