我需要数据库表中的工作表名称,但我的代码只是打印数组而不是从数据库中获取字符串或名称。如何在setTitle()函数中返回字符串。
$query = "select name from campaigns WHERE clients_id='66'";
$result = mysqli_query($con,$query) or die(mysqli_connect_error());
$objPHPExcel = new PHPExcel();
while ($row = mysqli_fetch_row($result)){
//if ($row['name'] !== $prevName) {
$newsheet = $objPHPExcel->createSheet();
$newsheet->setTitle($row['name']);
}