我有一个目前看起来像这样的数组: 它来自名称如name =“buyer_id []”
的表单Array (
[product_id] =>
Array (
[0] => 1
[1] => 2
[2] => 4
)
[name] =>
Array (
[0] => Paper Choco
[1] => Paper Fan Vanilla
[2] => Pink Prom
)
[staff_id] =>
Array (
[0] => 1
[1] => 1
[2] => 1
)
[category] =>
Array (
[0] => agent
[1] => agent
[2] => agent
)
[date] =>
Array (
[0] => 2014-08-22
[1] => 2014-08-22
[2] => 2014-08-22
)
[price] =>
Array (
[0] => 188
[1] => 887
[2] => 17
)
现在我希望它看起来像下面的数组,所以我可以将它传递到数据库中:
array(
array(
'product_id' => 1 ,
'name' => 'Paper Choco',
'category'=>'agent',
'staff_id'=> 1,
'date'=> '2014-08-22'
),
array(
'product_id' => 2 ,
'name' => 'Paper Fan Vanilla ',
'category'=>'agent',
'staff_id'=> 1,
'date'=> '2014-08-22'
),
array(
'product_id' => 4 ,
'name' => 'Pink Prom ',
'category'=>'agent',
'staff_id'=> 1,
'date'=> '2014-08-22'
)
);
我相信这是非常可能的,但我无法想办法呢
答案 0 :(得分:0)
$result = array();
foreach ($array as $key => $subarray) {
foreach ($subarray as $i => $value) {
if (!isset($result[$i])) {
$result[$i] = array();
}
$result[$i][$key] = $value;
}
}
答案 1 :(得分:0)
作为替代方案:
$data = array (
'product_id' => array ( 1, 2, 4 ),
'name' => array ( 'Paper Choco', 'Paper Fan Vanilla', 'Pink Prom' ),
'staff_id' => array ( 1, 1, 1 ),
'category' => array ( 'agent', 'agent', 'agent', ),
'date' => array ('2014-08-22', '2014-08-22', '2014-08-22' ),
'price' => array ( 188, 887, 17 ),
);
function transpose($array) {
array_unshift($array, null);
return call_user_func_array('array_map', $array);
}
$result = transpose($data);
array_walk(
$result,
function (&$value) use ($data) {
$value = array_combine(array_keys($data), $value);
}
);
var_dump($result);