SQL循环不将所有输入记录添加到临时表
我有一个由另一个人编写的SQL查询，它有一些问题。另外，我为这个代码的物理长度大声抱歉lol。我意识到它很长，但我认为有必要包括所有邮政编码，以便我可以提出我所拥有的问题。
查询接受邮政编码列表，循环将它们全部放入表变量中，然后根据我们的数据库查询该表。
我遇到的问题是，它只是循环并获取输入的前31个邮政编码。在下面的示例中，我输入了89个邮政编码，但临时表在打印时仅显示31个记录。
--this is your list of zip codes, place a comman after every zip
SET @zip_list =
'
30004,
31061,
30606,
27103,
28405,
53140,
60124,
60002,
44114,
77380,
75240,
77380,
75605,
72223,
72223,
76006,
78759,
76006,
50266,
50266,
50266,
49024,
78258,
67202,
92101,
92101,
92101,
92101,
90025,
90025,
55447,
90025,
92101,
90025,
55802,
55431,
55431,
55431,
37027,
02842,
10152,
10152,
02108,
07701,
08822,
94596,
94595,
55431,
92130,
92130,
95814,
95814,
93720,
95403,
94608,
92101,
19103,
08648,
18901,
18901,
18901,
19103,
85258,
85258,
85718,
85258,
85258,
98104,
98104,
97201,
89144,
92130,
92101,
92101,
97201,
97201,
97201,
63017,
63131,
22102,
21030,
22102,
22102,
20015,
22102,
20015,
20015,
20005,
06897,
' --this is your list of zip codes, place a , after every zip. Make sure the list is horizontal
---------------------------------
SET @zip_list = REPLACE(REPLACE(@zip_list,CHAR(13),''),CHAR(10),'') --Remove new line character to place zip codes all onto one line
print @zip_list
WHILE CHARINDEX(',', @zip_list) > 0
BEGIN
INSERT INTO @tbl_zip_list
--insert into @tbl_zip_list a substring equal to the first character from your string of zip codes + all the characters up to the first comma
SELECT SUBSTRING(@zip_list, 1, CHARINDEX(',', @zip_list) - 1)
--set the string of zip codes equal to your original string less the first zip code, which we just added to @tbl_zip_list
SET @zip_list = SUBSTRING(@zip_list, CHARINDEX(',', @zip_list) + 1, LEN(@zip_list))
END
----------------------------------
SELECT *
FROM @tbl_zip_list
SELECT oad.POSTAL_CODE_1,
o.CHANNEL
FROM dbo.OFFICE AS o
INNER JOIN dbo.OFFICE_ALIAS AS oa
ON o.OFFICE_ID = oa.OFFICE_ID
INNER JOIN dbo.OFFICE_ADDRESS AS oad
ON o.ADDRESS_1_ID = oad.OFFICE_ADDRESS_ID
WHERE oa.TRADE_FIRM = @trade_firm
AND o.CHANNEL != (SELECT f.channel
FROM dbo.FIRM AS f
INNER JOIN dbo.FIRM_ALIAS AS fa
ON f.FIRM_ID = fa.FIRM_ID
WHERE fa.trade_firm = @trade_firm)--will return the channel of the main firm */
AND EXISTS (SELECT 1
FROM @tbl_zip_list AS n1
WHERE n1.zip_list = oad.POSTAL_CODE_1) --this returns table of zip codes
------------------------------------------------
select f.channel as The_Default_Channel_For_Your_Firm_Is
from dbo.FIRM f INNER JOIN dbo.FIRM_ALIAS fa on f.FIRM_ID = fa.FIRM_ID
where fa.trade_firm = @trade_firm
我不知道如何修复循环，以便将所有89个邮政编码放入表中。下面是表的SQL-Server输出的屏幕截图。我只是不明白为什么它只有31条记录，应该是89条。
2 个答案:
答案 0 :(得分：2)
这样可行，我得到89回。
您必须声明@zip_list太小才能容纳整个字符串。
declare @tbl_zip_list table(zip varchar(10))
declare @zip_list varchar(8000)
--this is your list of zip codes, place a comman after every zip
SET @zip_list =
'
30004,
31061,
30606,
27103,
28405,
53140,
60124,
60002,
44114,
77380,
75240,
77380,
75605,
72223,
72223,
76006,
78759,
76006,
50266,
50266,
50266,
49024,
78258,
67202,
92101,
92101,
92101,
92101,
90025,
90025,
55447,
90025,
92101,
90025,
55802,
55431,
55431,
55431,
37027,
02842,
10152,
10152,
02108,
07701,
08822,
94596,
94595,
55431,
92130,
92130,
95814,
95814,
93720,
95403,
94608,
92101,
19103,
08648,
18901,
18901,
18901,
19103,
85258,
85258,
85718,
85258,
85258,
98104,
98104,
97201,
89144,
92130,
92101,
92101,
97201,
97201,
97201,
63017,
63131,
22102,
21030,
22102,
22102,
20015,
22102,
20015,
20015,
20005,
06897,
' --this is your list of zip codes, place a , after every zip. Make sure the list is horizontal
---------------------------------
SET @zip_list = REPLACE(REPLACE(@zip_list,CHAR(13),''),CHAR(10),'') --Remove new line character to place zip codes all onto one line
print @zip_list
WHILE CHARINDEX(',', @zip_list) > 0
BEGIN
INSERT INTO @tbl_zip_list
--insert into @tbl_zip_list a substring equal to the first character from your string of zip codes + all the characters up to the first comma
SELECT SUBSTRING(@zip_list, 1, CHARINDEX(',', @zip_list) - 1)
--set the string of zip codes equal to your original string less the first zip code, which we just added to @tbl_zip_list
SET @zip_list = SUBSTRING(@zip_list, CHARINDEX(',', @zip_list) + 1, LEN(@zip_list))
END
----------------------------------
SELECT *
FROM @tbl_zip_list
答案 1 :(得分：0)
如果在dbo.OFFICE_ADDRESS中确实没有匹配的邮政编码，则可能是另一个问题。要进行验证，请运行以下内容并查看您获得的结果数量（如果您只获得31，那么您知道这是因为您的邮政编码与列表中的邮政编码不匹配）。否则，很可能是JiggsJedi所说的，而且变量太短了
测试查询：
DECLARE @zip_list AS varchar(max)
DECLARE @tbl_zip_list TABLE (zip INT)
SET @zip_list =
'
30004,
31061,
30606,
27103,
28405,
53140,
60124,
60002,
44114,
77380,
75240,
77380,
75605,
72223,
72223,
76006,
78759,
76006,
50266,
50266,
50266,
49024,
78258,
67202,
92101,
92101,
92101,
92101,
90025,
90025,
55447,
90025,
92101,
90025,
55802,
55431,
55431,
55431,
37027,
02842,
10152,
10152,
02108,
07701,
08822,
94596,
94595,
55431,
92130,
92130,
95814,
95814,
93720,
95403,
94608,
92101,
19103,
08648,
18901,
18901,
18901,
19103,
85258,
85258,
85718,
85258,
85258,
98104,
98104,
97201,
89144,
92130,
92101,
92101,
97201,
97201,
97201,
63017,
63131,
22102,
21030,
22102,
22102,
20015,
22102,
20015,
20015,
20005,
06897,
' --this is your list of zip codes, place a , after every zip. Make sure the list is horizontal
---------------------------------
SET @zip_list = REPLACE(REPLACE(@zip_list,CHAR(13),''),CHAR(10),'') --Remove new line character to place zip codes all onto one line
print @zip_list
WHILE CHARINDEX(',', @zip_list) > 0
BEGIN
INSERT INTO @tbl_zip_list
--insert into @tbl_zip_list a substring equal to the first character from your string of zip codes + all the characters up to the first comma
SELECT SUBSTRING(@zip_list, 1, CHARINDEX(',', @zip_list) - 1)
--set the string of zip codes equal to your original string less the first zip code, which we just added to @tbl_zip_list
SET @zip_list = SUBSTRING(@zip_list, CHARINDEX(',', @zip_list) + 1, LEN(@zip_list))
END
----------------------------------
SELECT DISTINCT zip.zip
FROM @tbl_zip_list zip
JOIN dbo.OFFICE_ADDRESS AS oad ON zip.zip_list = oad.POSTAL_CODE_1
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