Question

所以我有这些字符串，我得到的包含很多我不想要的垃圾数据

"http://v20.lscache8.c.youtube.com/videoplayback?id=271de9756065677e&itag=17&ip=0.0.0.0&ipbits=0&expire=999999999999999999"&sparams=ip,ipbits,expireip,ipbits,expire,id,itag&signature=3DCD3F79E045F95B6AF661765F046FB0440FF01606A42661B3AF6BAF046F012549CC9BA34EBC80A9"

所以基本上我只是想让它通过字符串搜索videoplayback？id = *并且只是在videoplayback之间复制什么？id =和＆amp;

271de9756065677e

然后继续通过字符串并以相同的方式抓取签名

所以任何人都可以帮助我了解逻辑和示例如何做到这一点？

Answer 1

由于您的“包含垃圾数据的字符串”实际上是一个URL，因此您应该使用URL类看一下教程Parsing a URL

import java.net.*;
import java.io.*;

public class ParseURL {
    public static void main(String[] args) throws Exception {

        String url = "http://v20.lscache8.c.youtube.com/videoplayback?id=271de9756065677e&itag=17&ip=0.0.0.0&ipbits=0&expire=999999999999999999"&sparams=ip,ipbits,expireip,ipbits,expire,id,itag&signature=3DCD3F79E045F95B6AF661765F046FB0440FF01606A42661B3AF6BAF046F012549CC9BA34EBC80A9";
        URL aURL = new URL(url);

        System.out.println("protocol = " + aURL.getProtocol());
        System.out.println("authority = " + aURL.getAuthority());
        System.out.println("host = " + aURL.getHost());
        System.out.println("port = " + aURL.getPort());
        System.out.println("path = " + aURL.getPath());
        System.out.println("query = " + aURL.getQuery());
    }
}

输出应为：

protocol = http
authority = v20.lscache8.c.youtube.com:80
host = v20.lscache8.c.youtube.com
port = 80
path = /videoplayback
query = id=271de9756065677e&itag=17&ip=0.0.0.0&ipbits=0&expire=999999999999999999"&sparams=ip,ipbits,expireip,ipbits,expire,id,itag&signature=3DCD3F79E045F95B6AF661765F046FB0440FF01606A42661B3AF6BAF046F012549CC9BA34EBC80A9

要解析查询，请使用URLEncodedUtils

String url = "http://v20.lscache8.c.youtube.com/videoplayback?id=271de9756065677e&itag=17&ip=0.0.0.0&ipbits=0&expire=999999999999999999"&sparams=ip,ipbits,expireip,ipbits,expire,id,itag&signature=3DCD3F79E045F95B6AF661765F046FB0440FF01606A42661B3AF6BAF046F012549CC9BA34EBC80A9";
List<NameValuePair> params = URLEncodedUtils.parse(new URI(url), "UTF-8");

for (NameValuePair param : params) {
  System.out.println(param.getName() + "=" + param.getValue());
}

输出应为：

id=271de9756065677e
itag=17
ip=0.0.0.0
ipbits=0
expire=999999999999999999"
sparams=ip,ipbits,expireip,ipbits,expire,id,itag
signature=3DCD3F79E045F95B6AF661765F046FB0440FF01606A42661B3AF6BAF046F012549CC9BA34EBC80A9

获取包含垃圾数据的字符串的特定部分

1 个答案: