Question

我有这个路由：

resources :placements, only: :index do
    collection do
        put :update_all
        delete :destroy_all
    end
end
resources :designs, only: :index do
    collection do
        put :update_all
        delete :destroy_all
    end
end
# etc...

代码太多，看起来很难看。有没有办法得到这样的东西：

with_options only: :index, collection: { update_all: :put, destroy_all: :delete } do
    resources :placements
    resources :designs
end

提前致谢！：）

PS：这段代码看起来不错，但不起作用：（

Answer 1

Rails 4有routing concerns可用于执行此操作：

concern :standard_routing do
  collection do
    put :update_all
    delete :destroy_all
  end
end

resources :placements, only: :index, concerns: :standard_routing
resources :designs,    only: :index, concerns: :standard_routing

也就是说，路由DSL只是Ruby代码，do块只是块！因此，即使没有任何特殊支持，您也可以将其包装成一个简单易用的生成器，或者重用procs。

def standard_actions_for(*resources)
  Array(resources).each do |resource|
    self.resources resource, only: :index do
      collection do
        put :update_all
        delete :destroy_all
      end
    end
  end
end

standard_actions_for :placements, :designs

或：

standard_routing = Proc.new do
  collection do
    put :update_all
    delete :destroy_all
  end
end

resources :placements, only: index, &standard_routing
resources :designs,    only: index, &standard_routing

Rails在资源中使用相同的块进行路由

1 个答案: