Question

我试图让这个工作在每月的每个数字日。它没有||。任何想法如何使它与||？

一起使用

<script>
        var now = new Date();
        var day = ("0" + now.getDate()).slice(-2);
        var month = ("0" + (now.getMonth() + 1)).slice(-2);
        var today = (month) + "-" + (day) + "-" + now.getFullYear();
        var d = new Date();
        var n = d.getDate();
        if ((day == 13) || 
        (day == 16) ||
        (day == 19) ||
        (day == 22)) {
            document.getElementById("shift").innerHTML="A SHIFT" + " " + today;
        }
        else if ((day == 14) || 
        (day == 17) || 
        (day == 20) ||
        (day == 23)) {
            document.getElementById("shift").innerHTML="B SHIFT" + " " + today;
        }
        else ((day == 15) || 
        (day == 18) || 
        (day == 21) ||
        (day == 24)) {
            document.getElementById("shift").innerHTML="C SHIFT" + " " + today;
        }
</script>

Answer 1

您的代码不会产生任何输出，因为存在语法错误。修复似乎解决了您的问题 - jsFiddle。

您无法通过条件跟踪else。只有在您说else if时才有效。

else ((day == 15) || 
        (day == 18) || 
        (day == 21) ||
        (day == 24)) {

生成Uncaught SyntaxError: Unexpected token {或类似内容（取决于您的浏览器）。

正确的代码：

var now = new Date();
var day = ("0" + now.getDate()).slice(-2);
var month = ("0" + (now.getMonth() + 1)).slice(-2);
var today = (month) + "-" + (day) + "-" + now.getFullYear();
var d = new Date();
var n = d.getDate();

if ((day == 13) || (day == 16) || (day == 19) || (day == 22)) {
    document.getElementById("shift").innerHTML = "A SHIFT " + today;
} else if ((day == 14) || (day == 17) || (day == 20) || (day == 23)) {
    document.getElementById("shift").innerHTML = "B SHIFT " + today;
} else if ((day == 15) || (day == 18) || (day == 21) || (day == 24)) {
    document.getElementById("shift").innerHTML = "C SHIFT " + today;
}

Answer 2

或者，您可以重构整个解决方案并使目标更具可读性

<script language="javascript" type="text/javascript">
  // Get todays date and split it into dd, yyyy, mm components
  var now = new Date();
  var yyyy = now.getFullYear().toString();
  var mm = (now.getMonth()+1).toString();
  var dd  = now.getDate().toString();

  // Build padded_date in the format mm-dd-yyyy
  var padded_date = (mm[1]?mm:"0"+mm[0]) + '-' + (dd[1]?dd:"0"+dd[0]) + '-' + yyyy;
  alert(padded_date);

  // Determine the only variable that changes in your latter code
  var shift_alphabet;
  switch (parseInt(dd)) {
    case 13:
    case 16:
    case 19:
    case 22:  shift_alphabet = 'A';
              break;
    case 14:
    case 17:
    case 20:
    case 23:  shift_alphabet = 'B';
              break;
    case 15:
    case 18:
    case 21:
    case 24:  shift_alphabet = 'C';
              break;
    default:  shift_alphabet = 'A' // Assumption
              break;
  }

  // Using alerts because I don't have the HTML stuff
  alert(shift_alphabet);
  // Append shift alphabet to your output
  // document.getElementById("shift").innerHTML= shift_alphabet + " SHIFT" + " " + padded_date;

变量等于该月的数字日

2 个答案: