Question

我正在尝试将XML转换为Java代码。此XML位于不同的文件中;它将单词与数字（概率分布）匹配，如下所示：

<?xml version="1.0" encoding="UTF-8" ?>
<root>
   <Durapipe type="int">1</Durapipe>
   <EXPLAIN type="int">2</EXPLAIN>
   <woods type="int">2</woods>
   <hanging type="int">3</hanging>
   <hastily type="int">2</hastily>
   <localized type="int">1</localized>
   <Schuster type="int">5</Schuster>
   <regularize type="int">1</regularize>
   <LASR type="int">1</LASR>
   <LAST type="int">22</LAST>
   <Gelch type="int">2</Gelch>
   <Gelco type="int">26</Gelco>
   .......
</root>

我正在尝试将其转换为Java Map，这是我正在使用的代码：

XStream xstream = new XStream();
    @SuppressWarnings("unchecked")
    Map<String, Integer> englishCorpusProbDist = (Map<String, Integer>)xstream.fromXML(new File("LocationOfFileOnMyComputer/frequencies.xml"));

目前，每当我尝试运行上述Java代码时，我在控制台中都会遇到以下异常：

Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: root
at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.PackageAliasingMapper.realClass(PackageAliasingMapper.java:88)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ClassAliasingMapper.realClass(ClassAliasingMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ArrayMapper.realClass(ArrayMapper.java:74)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.SecurityMapper.realClass(SecurityMapper.java:71)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.CachingMapper.realClass(CachingMapper.java:47)
at com.thoughtworks.xstream.core.util.HierarchicalStreams.readClassType(HierarchicalStreams.java:29)
at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:133)
at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1185)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1169)
at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1133)
at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1075)
at ProductAttributeExtractor.main(ProductAttributeExtractor.java:23)

这是一个相关的帖子，但我的问题是增加了一层复杂性，因为我的XML与字符串匹配，不幸的是Java Map不能使用整数，它必须使用整数（这是非常令人沮丧的）：{{ 3}}

非常感谢您提供的任何帮助。提前谢谢！

Answer 1

您需要注册MapConverter，即实现Converter

的类

xstream.registerConverter（new MapEntryConverter（））;

希望有所帮助

Answer 2

Underscore-java库可以将xml转换为hashmap，反之亦然。我是该项目的维护者。 Live example

代码示例：

import com.github.underscore.lodash.U;

public class Main {
    public static void main(String[] args) {
      String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\" ?>"
    + "<root>"
    + "   <Durapipe type=\"int\">1</Durapipe>"
    + "   <EXPLAIN type=\"int\">2</EXPLAIN>"
    + "   <woods type=\"int\">2</woods>"
    + "   <hanging type=\"int\">3</hanging>"
    + "   <hastily type=\"int\">2</hastily>"
    + "   <localized type=\"int\">1</localized>"
    + "   <Schuster type=\"int\">5</Schuster>"
    + "   <regularize type=\"int\">1</regularize>"
    + "   <LASR type=\"int\">1</LASR>"
    + "   <LAST type=\"int\">22</LAST>"
    + "   <Gelch type=\"int\">2</Gelch>"
    + "   <Gelco type=\"int\">26</Gelco>"
    + "</root>";

    String result = U.fromXmlWithoutAttributes(xml).toString();
    // {Durapipe=1, EXPLAIN=2, woods=2, hanging=3, hastily=2, localized=1, Schuster=5, regularize=1, LASR=1, LAST=22, Gelch=2, Gelco=26}

    }
}

将XML转换为Java Map <string，integer =“”> </string，>

2 个答案: