我有一个文本文件text.txt
,日期安排如下。
name1
2010-01-02 (i)
2010-05-07 (i)
2010-06-12 (i)
name2
2010-01-02 (i)
2010-05-07 (i)
2010-06-12 (i)
name3
2011-01-05 (i)
2011-05-05 (i)
2011-06-14 (i)
我想把文件写成两列,如:
+---------------+-----+
| 2010-01-02 (i)|name1|
| 2010-05-07 (i)|name1|
| 2010-06-12 (i)|name1|
| 2010-01-02 (i)|name2|
| 2010-05-07 (i)|name2|
| 2010-06-12 (i)|name2|
| 2011-01-05 (i)|name3|
| 2011-05-05 (i)|name3|
| 2011-06-14 (i)|name3|
+---------------+-----+
此代码未按预期创建文件。
<?php
$path = "text.txt";
$file = file($path);
foreach($file as $value)
{
$name = "";
// if ( is found
if ( strpos($value, "(" ) !== false)
{
$date = $value;
$line = $date . "|" . $name;
$val = explode("|",$line);
//write only
$fp = fopen('data.csv', 'w');
fputcsv($fp, $val);
fclose($fp);
}
else
{
$name = $value;
//echo $name . "<br />";
}
}
?>
答案 0 :(得分:1)
$path = "text.txt";
$file = file($path);
$fp = fopen('data.csv', 'w+');
$title = array_shift($file);
foreach($file as $value) {
if (!strpos($value, "(" )){
$title = $value;
}
else {
$data = array_map('trim', array($value, $title));
fputcsv($fp , $data, '|');
}
}
fclose($fp);
答案 1 :(得分:0)
在这里,你可以试试这个:
<?php
$path = "text.txt";
$file = file($path);
$outputFile = 'data.csv';
$datein = '1998-09-21';
if(preg_match('/^\d{4}-\d{2}-\d{2}\s\(i\)$/', $datein)){
echo 'go';
}else{
echo 'no go';
}
$fp = fopen($outputFile,'w');
$name = "";
foreach($file as $value)
{
// match a date-line
if(preg_match('/^\d{4}-\d{2}-\d{2}\s\(i\)$/', $value)) {
$line = trim(preg_replace('/\s+/', ' ', $value)) . "|" . $name;
fwrite($fp,$line);
} else {
$name = $value;
}
}
fclose($fp);
?>
请注意,我将$name = '';
移到了循环之外,并将其更改为使用正则表达式。 trim(preg_replace...
函数用于删除读取行并将其存储到数组中时自动出现的换行符。