我一直试图尝试实现像
这样的东西<< < (文本框)(totalnumberofpages)> >>
对此有任何建议
提前致谢...
答案 0 :(得分:1)
如果您正在寻找DataView中的分页,那么启用分页所需要做的就是在数据视图上调用setItemsPerPage(int)。
请查看以下示例 JAVA 代码
public class RepeatingPage extends BasePage
{
private static final long serialVersionUID = 1L;
/**
* Constructor
*/
public RepeatingPage()
{
Iterator<Contact> contacts = new ContactDataProvider().iterator(0, 10);
RepeatingView repeating = new RepeatingView("repeating");
add(repeating);
int index = 0;
while (contacts.hasNext())
{
AbstractItem item = new AbstractItem(repeating.newChildId());
repeating.add(item);
Contact contact = contacts.next();
item.add(new ActionPanel("actions", new DetachableContactModel(contact)));
item.add(new Label("contactid", String.valueOf(contact.getId())));
item.add(new Label("firstname", contact.getFirstName()));
item.add(new Label("lastname", contact.getLastName()));
item.add(new Label("homephone", contact.getHomePhone()));
item.add(new Label("cellphone", contact.getCellPhone()));
final int idx = index;
item.add(AttributeModifier.replace("class", new AbstractReadOnlyModel<String>()
{
private static final long serialVersionUID = 1L;
@Override
public String getObject()
{
return (idx % 2 == 1) ? "even" : "odd";
}
}));
index++;
}
}
}
HTML 代码
<wicket:extend xmlns:wicket="http://wicket.apache.org">
<br/><br/>
<table cellspacing="0" class="dataview">
<tr>
<th>Actions</th>
<th>ID</th>
<th>First Name</th>
<th>Last Name</th>
<th>Home Phone</th>
<th>Cell Phone</th>
</tr>
<tr wicket:id="repeating">
<td><span wicket:id="actions">[actions]</span></td>
<td><span wicket:id="contactid">[contactid]</span> </td>
<td><span wicket:id="firstname">[firstname]</span></td>
<td><span wicket:id="lastname">[lastname]</span></td>
<td><span wicket:id="homephone">[homephone]</span></td>
<td><span wicket:id="cellphone">[cellphone]</span></td>
</tr>
</table>
</wicket:extend>
如果您需要在listView中进行分页,请检查PageableListView