Question

我使用arc4random_uniform（）从给定的String或Int中获取随机值。现在我想加入那些价值观。

var randomNumber = arc4random_uniform(9999) + 1000 // returns random number between 1000 and 9999 e.g. - 7501
let alphabet_array = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
let randomIndex = Int(arc4random_uniform(UInt32(alphabet_array.count)))
let random_alphabet = alphabet_array[randomIndex] // returns random alphabet e.g. - E

我想要的是像7501E一样显示7501和E

var str="\(randomNumber)\(random_alphabet)" // error

我收到以下错误：

Command /Applications/Xcode6-Beta.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swift failed with exit code 254

请帮助我如何一起显示。

Answer 1

正确的标点符号可以正常工作：

var randomNumber = arc4random_uniform(999) + 1000 
// returns random number between 1000 and 9999 e.g. - 7501 NOTE 999 not 9999

let alphabet_array = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"] 
// Note missing "=" in OP

let randomIndex = Int(arc4random_uniform(UInt32(alphabet_array.count)))

let random_alphabet = alphabet_array[randomIndex] // returns random alphabet e.g. - E

var str = "\(randomNumber)\(random_alphabet)" // e.g. 1197A

Answer 2

您也可以将随机数转换为字符串，然后将它们一起添加，而不是使用字符串插值：

let str = randomNumber.description + random_alphabet

在Apple Swift中连接NSString和Int

2 个答案: