传递DBI时的perl错误 - >执行IN子句的值

时间:2014-06-23 14:19:40

标签: perl dbi

我有一个查询来计算基于文档的某个半径范围内的对象:http://www.plumislandmedia.net/mysql/haversine-mysql-nearest-loc/

它非常好用,但我只想搜索特定类型的对象,这会导致问题;

代码如下所示:

my $sql = "SELECT *
 FROM (
 SELECT b.*, pr.postcode, pr.prize, pr.title, pr.collection, pr.redeemed, pr.delivery, pr.archived, bt.category,
        p.radius,
        p.distance_unit
                 * DEGREES(ACOS(COS(RADIANS(p.latpoint))
                 * COS(RADIANS(b.lat))
                 * COS(RADIANS(p.longpoint - b.lng))
                 + SIN(RADIANS(p.latpoint))
                 * SIN(RADIANS(b.lat)))) AS distance
  FROM bubbles AS b, bubble_prizes AS pr, bubble_types AS bt
  JOIN (   /* these are the query parameters */
        SELECT  ?  AS latpoint, ? AS longpoint,
                ? AS radius,      ? AS distance_unit
    ) AS p
  WHERE b.lat
     BETWEEN p.latpoint  - (p.radius / p.distance_unit)
         AND p.latpoint  + (p.radius / p.distance_unit)
    AND b.lng
     BETWEEN p.longpoint - (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
         AND p.longpoint + (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
    AND pr.bubble = b.id
    AND b.type IN ?
    AND b.type = bt.type
 ) AS d
 WHERE distance <= radius
 ORDER BY distance";    

然后我做

my $points = $y->dbh->prepare($sql);
$results  = $points->execute($lat, $lng, $rad, $units, '(type1, type2)');

其中&#39;(type1,type2)&#39;应该传递给

b.type IN ?

(靠近SQL的底部)。

我已经尝试过各种各样的方式,我可以想到逃避这个字符串以便它起作用(包括很多方式,显然是疯了但我已经绝望了)inc

'(type1, type2)'
'\(\'type1\', \'type2\'\)'
'(\'type1\', \'type2\')'
"('type1', 'type2')"

等(我已经尝试了很多我无法记住的东西。)

无论我尝试什么,我都会遇到

形式的SQL错误
DBD::mysql::st execute failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''(type1, type2)'
    AND b.type = bt.type
 ) AS d
 WHERE distance <= radius'

根据我试图逃避字符串的方式,错误消息略有不同,但始终与sql的相同部分有关。

我现在认为逃避不是我的问题而且我错过了一些关于执行的事情。如果我在DB中运行代码,它可以正常使用IN语句,即b.type IN(&#39; type1&#39;,&#39; type2&#39;)工作正常。

有人可以开导我吗?我该怎么做?

由于

1 个答案:

答案 0 :(得分:5)

您需要在IN (...)语句中使用占位符。 execute()的整个要点是避免SQL注入,并且您基本上是在尝试在那里注入SQL。您可以像这样制作一个动态的占位符列表:

my @types = qw(type1 type2);
my $placeholders = join ", ", ("?") x @types;
my $sql = "...
        b.typeID IN ($placeholders)
    ...";
my $points = $y->dbh->prepare($sql);
$results  = $points->execute($lat, $lng, $rad, $units, @types);