Question

我使用上一个表单中的信息来创建一个混乱的字符串。我使用此字符串来命名我在下面的代码中创建的表：

// get data that sent from form 
$TN = mysql_real_escape_string($_POST['name']);
$TQ = mysql_real_escape_string($_POST['q']);
$CR = mysql_real_escape_string($_POST['creator']);

//Add Randomness to String
$datetime=date("d/m/y"); //create date time
$R1=rand(5000, 150);
$R2=rand(5000, 10000);
$R3=rand(5000, 15000000);

//Create String called URL
$URL = $TN . $R1 . $TQ . $R2 . $CR . $R3;

//Eliminate Spaces
$URL=str_replace(" ","#%","$URL");

//echo $URL;

//add name of table in a table containing the names of these tables
mysql_select_db("$db_name")or die("cannot select DB");
$sql="INSERT INTO $tbl_name(URL,topic)VALUES('$URL','$TQ')";
$result=mysql_query($sql);

//Create the Table
$sql="CREATE TABLE ".$URL."(Image BLOB,Rating INT(255),Id INT KEY AUTO_INCREMENT)";
$result=mysql_query($sql);

这段代码很棒！只要$ TQ，$ TN或$ CR在单词中包含空格，它就会失败！以下是错误消息：表必须至少有一列

有谁知道如何解决这个问题？

Answer 1

您必须用`：

将表名括起来

$sql="CREATE TABLE `".$URL."` (Image BLOB,Rating INT(255),Id INT KEY AUTO_INCREMENT)";

MYSQL问题（创建表）

1 个答案: