需要SQL Group By和AGGREGATE帮助

Question

我有两张桌子......

• 订单（orderNumber，orderDate，shippedDate，requiredDate，status，customerNumber）和
• 订单明细（ORDERNUMBER，PRODUCTCODE，quantityOrdered，priceEach，orderLineNumber）

我试图返回这样的查询...

+----------------------------------+--------------------+
| DATEDIFF(shippedDate, orderDate) | COUNT(shippedDate) |
+----------------------------------+--------------------+
|                                1 |                 50 |
|                                2 |                 49 |
|                                3 |                 52 |
|                                4 |                 52 |
|                                5 |                 59 |
|                                6 |                 45 |
|                                7 |                  2 |
|                                8 |                  2 |
|                               65 |                  1 |
+----------------------------------+--------------------+

但是我没有得到它。我知道我必须做一个分组并使用DateDiff（）和Count（）......

我试过这个但是不对 mysql：

select DATEDIFF(shippedDate,orderDate), COUNT(shippedDate) from Orders Group by shippedDate;

有什么建议吗？

Answer 1

您需要group by datediff()：

select DATEDIFF(shippedDate, orderDate), COUNT(shippedDate)
from Orders
Group by DATEDIFF(shippedDate, orderDate);

Answer 2

您需要在group by语句中添加datediff（shippedDate，orderDate）而不是shippingDate