如何创建数字列表，然后用比它们高的第一个偶数数替换列表中的奇数？

Question

例如：([3,85,44,71,9,5])会返回([4,86,44,72,10,6])

用户输入信息，所以我必须创建一个空列表吗？

很多人会很感激

谢谢！

Answer 1

list1 = [3,85,44,71,9,5]
list2 = [x + (x%2) for x in list1]

注意x%2对于奇数是1而对偶数是0。

Answer 2

使用lambda和三元运算符：

list1 = [3,85,44,71,9,5]
map(lambda x: x if x%2==0 else x+1, list1) 
[4, 86, 44, 72, 10, 6]

P.S。相关讨论：Python List Comprehension Vs. Map

Answer 3

list = []
num = 0
while (num != -1):
   num = input("Enter number; enter -1 to end: ")
   if (num != -1):
      list.append(num+1)

Answer 4

使用modulo：

arr = [3,85,44,71,9,5]
arr = [item + item%2 for item in arr]

运行如下：

>>> arr = [3,85,44,71,9,5]
>>> arr = [item + item%2 for item in arr]
>>> arr
[4, 86, 44, 72, 10, 6]
>>> 

%就是这样的：

>>> 9%2 #Gives 1, because 9/2 is 4 remainder 1
1
>>> 10%2 #Gives 0, because 10/2 is 5 remainder 0
0
>>>