Question

首先，我想提前感谢您的帮助。

我有一个像这样结构的数组：

array(18) {
  ["department"]=>
  string(14) "Administration"
  ["employee"]=>
  string(13) "Joe Smith"
  ["times"]=>
  string(6) "7:00am"
  ["timee"]=>
  string(6) "7:00pm"
  ["regular"]=>
  int(8)
  ["overtime"]=>
  int(4)
  ["d_overtime"]=>
  int(4)
  ["total"]=>
  int(12)
  ["cost"]=>
  int(28)
  ["date"]=>
  string(12) "May 27, 2014"
  ["curdp"]=>
  int(28)
  ["mtddp"]=>
  int(28)
  ["rev"]=>
  string(10) "35073.8900"
  ["dp2rev"]=>
  string(5) "0.08%"
  ["mtd2rev2013"]=>
  string(4) "-na-"
  ["mtdpay2rev"]=>
  string(5) "0.08%"
  ["budget"]=>
  string(4) "1.80"
  ["counter"]=>
  NULL
}

我需要能够找到具有相同“日期”值的数组中的最后一个条目。例如，我需要在数组中找到所有May 27,2014值并显示最后一个条目。

再次感谢你。

Answer 1

让输入数据在$ data

中

$resultArr = array();
$filteredByDateArr = array();

    foreach($data as $entry)
    {    
if($entry['date']=='May 27, 2014')
    $resultArr[] = $entry;

$filteredByDateArr[$entry['date']][] = $entry;

    }

    //last entry
    var_dump($resultArr[count($resultArr)-1]);
var_dump($filteredByDateArr);

//This $filteredByDateArr is the array that will give you date respective data.
//So if you want to find the last entry of say any date $date

//You can get it by:

var_dump($filteredByDateArr[$date][count($filteredByDateArr[$date])-1]);

删除重复的条目并保持最后一个条目

1 个答案: