如何显示两个选择的结果表＆＃39;？ SQL

Question

我有2个问题：
第一次查询：

select TableB.name, count(TableB.name) from TableB group by TableB.name

结果：

 name | count
 Jack | 2
 Marry| 1

和
第二次查询：

select DISTINCT TableA.kName, TableA.Value from TableA inner join TableB 
ON
TableA.kName=TableB.name

结果：

kName | Value
Jack  | 1
Marry | 3

但我需要结果表：

kName | Value | newColumn
Jack  |  1    | 2
Marry |  3    | 1

其中newColumn是第一次查询的结果，怎么办呢？求助。

也许

select DISTINCT TableA.kName, TableA.value, 
(select TableB.name, count(TableB.name) from TableB group by TableB.name) 
AS 
newColumn from TableA inner join TableB ON TableA.kName=TableB.name

但这不起作用：（

Answer 1

尝试此查询

SELECT tableB.name, tableA.value, count(tableB.name) as newColum FROM tableB
JOIN tableA ON tableB.name = tableA.kname
GROUP BY tableB.name,tableA.value

Answer 2

select kname, value, "newColumn"
from
    (
        select name, count(name) as "newColumn"
        from tb
        group by name
    ) tb
    inner join
    (
        select distinct kname, value
        from ta
    ) ta ta.kname = tb.name