我想用db_host
替换密钥(即addons_path
,$$$$
)的值。
输入文本文件包含以下内容:
#Test.txt#
addons_path=/bin/root
admin_passwd = abctest
auto_reload = False
csv_internal_sep = ,
db_host = 90.0.0.1
输出文本文件:
#Test2.txt#
admin_passwd = abctest
auto_reload = False
csv_internal_sep = ,
db_host = $$$$$
我想替换特定键的值并将其写入文件,而不是用新文件替换旧文件。
以下功能为我提供了替换特定键值的正确输出 import fileinput 来自pprint import pprint as p
replace_with = '7777'
key = 'db_host'
fileref = open('/Files/replace_key/test','r+')
line = fileref.readline()
config = []
while line:
split_line = line.split('=')
if len(split_line ) == 2:
config.append( ( split_line[0].strip(' \n'),split_line[1].strip(' \n') ) )
print line
line = fileref.readline()
fileref.close()
config = dict(config)
print config
config.update({'db_host':replace_with})
p(config)
但我无法将其应用于整个文本文件。
答案 0 :(得分:1)
如果您想使用Python,可以使用以下函数:
def replace_in_file(filename, key, new_value):
f = open(filename, "r")
lines = f.readlines()
f.close()
for i, line in enumerate(lines):
if line.split('=')[0].strip(' \n') == key:
lines[i] = key + ' = ' + new_value + '\n'
f = open(filename, "w")
f.write("".join(lines))
f.close()
replace_in_file("file.txt", 'db_host', "7777")
答案 1 :(得分:0)
使用UNIX工具可以更简单地实现这一点。
然而,这是我的解决方案:
bash-4.3$ cat - > test.txt
#Test.txt#
addons_path=/bin/root
admin_passwd = abctest
auto_reload = False
csv_internal_sep = ,
db_host = 90.0.0.1
bash-4.3$ python
Python 2.7.6 (default, Apr 28 2014, 00:50:45)
[GCC 4.8.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> with open("test.txt", "r") as f:
... pairs = (line.split("=", 1) for line in f if not line.startswith("#"))
... d = dict([(k.strip(), v.strip()) for (k, v) in pairs])
...
>>> d["db_host"] = "$$$$"
>>> with open("out.txt", "w") as f:
... f.write("\n".join(["{0:s}={1:s}".format(k, v) for k, v in d.items()]))
...
>>>
bash-4.3$ cat out.txt
db_host=$$$$
admin_passwd=abctest
auto_reload=False
csv_internal_sep=,
addons_path=/bin/rootbash-4.3$
=
的键/值对解析为dict
(忽略评论)。db_host
键。=
作为键/值分隔符写出字典。享受:)
更新:作为一组可重复使用的功能:
def read_config(filename):
with open(filename, "r") as f:
pairs = (line.split("=", 1) for line in f if not line.startswith("#"))
return dict([(k.strip(), v.strip()) for (k, v) in pairs])
def write_config(d, filename):
with open(filename, "w") as f:
f.write("\n".join(["{0:s}={1:s}".format(k, v) for k, v in d.items()]))
答案 2 :(得分:0)
这样的事情怎么样?
def replace_string(s):
s = s.replace('db_host','$$$$')
return s
with open('test.txt','r') as fo:
line = fo.read() # you could use strip() or split() additionally
new_string = replace_string(line)
答案 3 :(得分:0)
使用fileinput
模块。
import fileinput
for line in fileinput.input('data.txt',backup='.bak',inplace=1):
print line.rstrip().replace('Python','Perl')
#or print line.replace('Python','Perl'),