Question

我有一个填充0和1的字符串，并希望得到一个整数：（Arduino UNO的平台）

String bitString = ""; 
int Number;
int tmp;

bitString = "";
  for (i=1;i<=10;i++)
  {
    tmp= analogRead (A0);
    bitString +=  tmp % 2;
    delay(50);
  }
// now bitString contains for example "10100110" 
// Number = bitstring to int <-------------
// In the end I want that the variable Number contains the integer 166

Answer 1

你根本不需要一串比特。就这样做：

  int n = 0;  // unsigned might be better here
  for (i = 0; i < 10; i++) {
    int bit = analogRead(A0) & 1;
    putchar('0' + bit);
    n = (n << 1) | bit;
    delay(50);
  }
  printf("\n%d\n", n);

Answer 2

你可以使用strtol（）函数：

#include <stdio.h>
#include <stdlib.h>

int main(int argc, const char * argv[])
{
char *a = "10100110";

int b = (int) strtol(a, NULL, 2);

printf("%d", b); //prints 166

return 0;
}

在C或C ++中将二进制字符串转换为int

2 个答案: