Question

所以我错误地将一个int传递给一个函数参数，期望一个指向const对象的指针，我从GCC得到了这个警告：

jni/../../../Source/Controller/UserExperienceManager.cpp: In member function 'void CUserExperienceManager::SendUXPToPOS(Types::CString)':
jni/../../../Source/Controller/UserExperienceManager.cpp:243:78: warning: invalid conversion from 'int' to 'const WebService_POSAgent::CDataCheck*' [-fpermissive]
jni/../../../../../Core/WebServices/Services/POSAgent/POSAgent.h:80:18: warning:   initializing argument 2 of 'CEvent& WebService_POSAgent::CPOSAgent::AddUserExperienceID(Types::CString, const WebService_POSAgent::CDataCheck*, Types::CString)' [-fpermissive]

我试图创建一个可重现的样本，但我无法做到，我不能在这里分享太多的代码。我在MSVC9上编译了同样的东西，它给了我一个错误。我很震惊，我没有收到GCC的错误！谁知道为什么？以下是一些简单的片段：

功能声明（类成员函数）：

CEvent& AddUserExperienceID(CString userExperienceId, CDataCheck const* check, CString requestId = REQUEST_ID);

功能调用站点：

int nCheckNum = /*some value*/;
CPOSAgent::Instance().AddUserExperienceID(m_UserExperienceId, nCheckNum);

Answer 1

您正在使用-fpermissive设置编译该代码，该代码会将错误降级为警告。

 -fpermissive
  Downgrade some diagnostics about nonconformant code from errors to warnings.
  Thus, using -fpermissive will allow some nonconforming code to compile.

What does the fpermissive flag do?

GCC允许隐式int到指针转换？

1 个答案: