我有3个表Check_In
,Check_Out
,Patient_Detail
,我想用vb.net表单立即插入它们。我已经为这些表格创建了关系。它没有显示任何错误,也不起作用。我试图找到解决方案2天我没有更多我亲爱的去做.plz帮助
If DialogResult = Windows.Forms.DialogResult.OK Then
'' Try
cmd = New SqlCommand
Dim cmd2 As New SqlCommand
Dim cmd3 As New SqlCommand
cmd2.Connection = cn
cmd3.Connection = cn
cmd.Connection = cn
'cmd.CommandText = "INSERT INTO Table_PatientDetail (Patient_ID , Patient_Name , Age,Sex , Phone_Number , Address , Service , Transfer , Patient_Result ) VALUE (" & .PatientIDPatientInformation.Text & "','" & .PatientNamePatientInformation.Text & "','" & .AgePatientInformation.Text & "','" & .ComboBox1.Text & "','" & .PhoneNumPatientInformation.Text & "','" & .AddressPatientInformation.Text & "','" & .Cboservice.SelectedValue & "','" & .TransferPatientInformation.Text & "','" & .TransferPatientInformation.Text & "')"
cmd.CommandText = "INSERT INTO Table_PatientDetail (Patient_ID , Patient_Name , Age,Sex , Phone_Number , Address, Check_In_ID, Check_Out_ID , Service , Transfer , Patient_Result ) VALUES (@Patient_ID , @Patient_Name , @Age,Sex , @Phone_Number , @Address, @Check_In_ID , Check_Out_ID@ , @Service , @Transfer , @Patient_Result)"
cmd.Parameters.AddWithValue("@Patient_ID", .PatientIDPatientInformation.Text)
cmd.Parameters.AddWithValue("@Patient_Name", .PatientNamePatientInformation.Text)
cmd.Parameters.AddWithValue("@Age", .AgePatientInformation.Text)
cmd.Parameters.AddWithValue("@Sex", .ComboBox1.Text)
cmd.Parameters.AddWithValue("@Phone_Number", .PhoneNumPatientInformation.Text)
cmd.Parameters.AddWithValue("@Address", .AddressPatientInformation.Text)
cmd.Parameters.AddWithValue("@Service", .Cboservice.SelectedValue)
cmd.Parameters.AddWithValue("@Transfer", .TransferPatientInformation.Text)
cmd.Parameters.AddWithValue("@Patient_Result", .ComboBox3.Text)
cmd2.CommandText = " INSERT INTO Table Table_Check_in ( Check_In_ID , Check_In_Date , Illness_ID) VALUES ( @Check_In_ID , @Check_In_Date ,@CI_Illness_ID )"
cmd.Parameters.AddWithValue("@Check_In_ID", .CIID.Text)
cmd.Parameters.AddWithValue("@Check_In_Date", .CheckinDateTimePicker1.Text)
cmd.Parameters.AddWithValue("@CI_Illness_ID", .CheckInillnessComboBox.SelectedValue)
cmd3.CommandText = " INSERT INTO Table Table_Check_Out ( Check_Out_ID , Check_Out_Date , Illness_ID) VALUES ( @Check_Out_ID , @Check_Out_Date ,@CO_Illness_ID )"
cmd.Parameters.AddWithValue("@Check_Out_ID", .COID.Text)
cmd.Parameters.AddWithValue("@Check_Out_Date", .CheckoutDateTimePicker2.Text)
cmd.Parameters.AddWithValue("@CO_Illness_ID", .CheckOutillnessComboBox.SelectedValue)
cmd.ExecuteNonQuery()
cmd2.ExecuteNonQuery()
cmd3.ExecuteNonQuery()
Catch ex As Exception
MsgBox(ex.ToString)
End Try
End if
答案 0 :(得分:0)
在第二个和第三个插入命令中,您要添加到第一个命令的参数的一个快速观察,不应该是cmd2和cmd3吗?
cmd2.CommandText = " INSERT INTO Table Table_Check_in ( Check_In_ID , Check_In_Date , Illness_ID) VALUES ( @Check_In_ID , @Check_In_Date ,@CI_Illness_ID )"
cmd2.Parameters.AddWithValue("@Check_In_ID", .CIID.Text)
cmd2.Parameters.AddWithValue("@Check_In_Date", .CheckinDateTimePicker1.Text)
cmd2.Parameters.AddWithValue("@CI_Illness_ID", .CheckInillnessComboBox.SelectedValue)
cmd3.CommandText = " INSERT INTO Table Table_Check_Out ( Check_Out_ID , Check_Out_Date , Illness_ID) VALUES ( @Check_Out_ID , @Check_Out_Date ,@CO_Illness_ID )"
cmd3.Parameters.AddWithValue("@Check_Out_ID", .COID.Text)
cmd3.Parameters.AddWithValue("@Check_Out_Date", .CheckoutDateTimePicker2.Text)
cmd3.Parameters.AddWithValue("@CO_Illness_ID", .CheckOutillnessComboBox.SelectedValue)